Let H= {*] 1}. * : 8x² + 6y² s which represents the set of points on and inside an ellipse in the xy-plane. Find two specific examples-two vectors, and a vector and a scalar-to show that H is not a subspace of R² H is not a subspace of R² because the two vectors show that H (Use a comma to separate vectors as needed.) closed under

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
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Chapter2: Second-order Linear Odes
Section: Chapter Questions
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Second image is an example, only do problem in first image

{*]:0²
: 8x² + 6y² ≤1
, which represents the set of points on and inside an ellipse in the xy-plane. Find two specific examples-two vectors, and a vector and a scalar-to show that H is not a subspace of R².
Let H=
H is not a subspace of R² because the two vectors
(Use a comma to separate vectors as needed.)
show that H
closed under
Transcribed Image Text:{*]:0² : 8x² + 6y² ≤1 , which represents the set of points on and inside an ellipse in the xy-plane. Find two specific examples-two vectors, and a vector and a scalar-to show that H is not a subspace of R². Let H= H is not a subspace of R² because the two vectors (Use a comma to separate vectors as needed.) show that H closed under
* {;] +²+7+)}.*
4x² + y²
Let H=
which represents the set of points on and inside an ellipse in the xy-plane. Find two specific examples-two vectors, and a vector and a scalar-to show that H is not a subspace of R².
H is not a subspace of R² because the two vectors
NI→
0
show that H is not closed under addition.
(Use a comma to separate vectors as needed.)
H is not a subspace of R² because the scalar 3 and the vector 1 show that H is not closed under addition.
That's incorrect.
Correct answers:
0.33
, is not, scalar multiplication.
-0.67
Your answers: 1, is not, addition.
Similar question
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X
Transcribed Image Text:* {;] +²+7+)}.* 4x² + y² Let H= which represents the set of points on and inside an ellipse in the xy-plane. Find two specific examples-two vectors, and a vector and a scalar-to show that H is not a subspace of R². H is not a subspace of R² because the two vectors NI→ 0 show that H is not closed under addition. (Use a comma to separate vectors as needed.) H is not a subspace of R² because the scalar 3 and the vector 1 show that H is not closed under addition. That's incorrect. Correct answers: 0.33 , is not, scalar multiplication. -0.67 Your answers: 1, is not, addition. Similar question Next question X
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