Let ginl=√1+an To find: (i) g'(x) cliij Domain of g(x) Domain of gix. Q using definition @ g'xl lim gx+h)-g(x) h-to h By = I'm √₁+2(x+h) -√√1+2x ho h = lim (√₁+2in+h)-√₁+2x) (√²+2(x+8) + √₁+2×) ho h √1+21x+h) + √1+2x) = lim hto = lim h-to h-to lim h-to 1+2(x+h)-(1+2x) h ( √1+2(1+h) + √1+2×) 1+2x+2h-1-2X h (√₁+2(x+h) + √²+2x) 2h h(√√1+2+6) + √1+2x 2 √√1+2+3h + 2 √1+2n + √1+2x √₁+2x = 2 √√₁+2 a g'(x g'(x) Domain of 9 2√1+2x √1+2X 90x0: 1+ax>0 2017-1 기호 Domain g(x) is (900) Domain of g'ox is also (-1/200) of

Advanced Engineering Mathematics
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Author:Erwin Kreyszig
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Chapter2: Second-order Linear Odes
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CV
Let girl = √√1+28
To find:
(1) g'(x)
ciij
iii)
Domain of gin)
Domain of girl.
By using
9x1= lim gix+h)-glu)
ho
h
= lim
ho
= 1m √√1+2(x+h) -√√1+2x
hto
= lim
=
-
= lim
hto
definition :
(1
=
hto
lim
hto
lim
ho
h
√₁+2(x+h1-√₁+2x) (√₁+2in+B) + √[1+2x)
h
(√₁+2(x+h) + √1+24)
1+2(x+h)-(1+3x)
h ( √1+2(n+h) + √₁+24)
1+2n+2h-1-21
h (√1+2(x+h1+√√√+2×)
2h
h (√√√1+2+h) + √1+2×
2
1+2n+2h + √√√₁+2n
=
√+an+ah
2
1+2n + √√1+24
2
2 √₁+ 2n
to
3
+ g'(x)
-
→g'(x)
=
Domain of
2
2√√√√+2K
1+2X
нях
g(x:
1+2x>0
120-1
기
17-1/22
Domain of girl is
27-1
(-1900)
Domain of glow is also (-1/200)
Transcribed Image Text:CV Let girl = √√1+28 To find: (1) g'(x) ciij iii) Domain of gin) Domain of girl. By using 9x1= lim gix+h)-glu) ho h = lim ho = 1m √√1+2(x+h) -√√1+2x hto = lim = - = lim hto definition : (1 = hto lim hto lim ho h √₁+2(x+h1-√₁+2x) (√₁+2in+B) + √[1+2x) h (√₁+2(x+h) + √1+24) 1+2(x+h)-(1+3x) h ( √1+2(n+h) + √₁+24) 1+2n+2h-1-21 h (√1+2(x+h1+√√√+2×) 2h h (√√√1+2+h) + √1+2× 2 1+2n+2h + √√√₁+2n = √+an+ah 2 1+2n + √√1+24 2 2 √₁+ 2n to 3 + g'(x) - →g'(x) = Domain of 2 2√√√√+2K 1+2X нях g(x: 1+2x>0 120-1 기 17-1/22 Domain of girl is 27-1 (-1900) Domain of glow is also (-1/200)
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