Let G be a group of order 60. If the Sylow 3-subgroup is normal,show that the Sylow 5-subgroup is normal.

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
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Let G be a group of order 60. If the Sylow 3-subgroup is normal,
show that the Sylow 5-subgroup is normal.

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Step 1

Given that G be a group of order 60. If the Sylow 3-subgroup is normal.

We have to show that the Sylow 5-subgroup is normal.

Assume that the Sylow 5-subgroup is not normal.

Let n5 be the number of all the Sylow 5-subgroup of H.

We know that G=60=512

Hence, by Sylow third theorem, we see that n5=1mod5 and n5 divides 12.

Since, n5 divides 12.

Hence, we see that n51,2,3,4,6,12.

Since, n5=1mod5, hence we can check that n51,6.

Since, the Sylow 5-subgroup are not normal, hence, we can conclude that n51 and n5=6.

Let K1, K2 ,....., K6 be the 6 Sylow 5-subgroup.

We see that the order of each Ki is 5, therefore they are cyclic.

It follows that each Ki contains 4 elements of order 5.

Therefore, there are 46=24 elements of order 5 in these subgroups.

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