Let G be a group and suppose that G only has finitely many distinct subgroups. Show that |G| < ∞.
Let G be a group and suppose that G only has finitely many distinct subgroups. Show that |G| < ∞.
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
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Let G be a group and suppose that G only has finitely many distinct subgroups. Show that |G| < ∞.
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Step 1
If possible let G is of infinite order .In particular let G = {a1,a2,...,an,...} .Let us consider the subgroups
H1= < a1> , that is the subgroup generated a single element by a1, for some a1 in G.
H2 = < a1,a2 >, that is the subgroup generated a single element by a1 , a2 for some a1 ,a2 in G.
Similarly, we get
Hn= < a1,a2,...,an> , that is the subgroup generated a single element by a1,a2,...,an , for some a1,a2,...,an in G and so on.
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