Let G be a group and let H and K be subgroups of G so that H is not contained in K and K is not contained in H. Prove that HU K is not a subgroup of G.

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Let \( G \) be a group and let \( H \) and \( K \) be subgroups of \( G \) so that \( H \) is not contained in \( K \) and \( K \) is not contained in \( H \). Prove that \( H \cup K \) is not a subgroup of \( G \).
Transcribed Image Text:Let \( G \) be a group and let \( H \) and \( K \) be subgroups of \( G \) so that \( H \) is not contained in \( K \) and \( K \) is not contained in \( H \). Prove that \( H \cup K \) is not a subgroup of \( G \).
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Step 1

Given that

G be a group and H and K are two subgroup

s.t H is not contained in K and  K is not contained in H.

To prove HuK is not a subgroup of G.

 

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