Let f(z) be a rational function with no poles on the positive real axis, and suppose that lim Pf(z) lim zf(z) = 0. - 2-0 Show that [x²-¹ f(x) dx = XP-1 0 ㅠ sin p ΣRes{(-2)²-¹(2)}, where the sum is over all the poles of f(z). [Hint. Consider the integral (-2)-1 f(z)dz = fre(p-1) ln(-2) f(z)dz, where I is a suitable contour.]

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter4: Polynomial And Rational Functions
Section: Chapter Questions
Problem 15T
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Assume that p is real.

Let f(z) be a rational function with no poles on the positive real axis, and suppose that
lim z f(z) = lim zºf(z) = 0.
z→0
Z→∞
Show that
[² x²-1¹ f(x) dx =
XP-
π
sin p
Res{(-2)-¹1f(z)},
where the sum is over all the poles of f(z).
[Hint. Consider the integral f(-2)-¹ f(2)dz = f₁ ep−1) ¹(-2) f(z)dz, where I is a suitable
contour.]
Transcribed Image Text:Let f(z) be a rational function with no poles on the positive real axis, and suppose that lim z f(z) = lim zºf(z) = 0. z→0 Z→∞ Show that [² x²-1¹ f(x) dx = XP- π sin p Res{(-2)-¹1f(z)}, where the sum is over all the poles of f(z). [Hint. Consider the integral f(-2)-¹ f(2)dz = f₁ ep−1) ¹(-2) f(z)dz, where I is a suitable contour.]
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