Let f(z) be a rational function with no poles on the positive real axis, and suppose that lim Pf(z) lim zf(z) = 0. - 2-0 Show that [x²-¹ f(x) dx = XP-1 0 ㅠ sin p ΣRes{(-2)²-¹(2)}, where the sum is over all the poles of f(z). [Hint. Consider the integral (-2)-1 f(z)dz = fre(p-1) ln(-2) f(z)dz, where I is a suitable contour.]
Let f(z) be a rational function with no poles on the positive real axis, and suppose that lim Pf(z) lim zf(z) = 0. - 2-0 Show that [x²-¹ f(x) dx = XP-1 0 ㅠ sin p ΣRes{(-2)²-¹(2)}, where the sum is over all the poles of f(z). [Hint. Consider the integral (-2)-1 f(z)dz = fre(p-1) ln(-2) f(z)dz, where I is a suitable contour.]
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter4: Polynomial And Rational Functions
Section: Chapter Questions
Problem 15T
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100%
Assume that p is real.
![Let f(z) be a rational function with no poles on the positive real axis, and suppose that
lim z f(z) = lim zºf(z) = 0.
z→0
Z→∞
Show that
[² x²-1¹ f(x) dx =
XP-
π
sin p
Res{(-2)-¹1f(z)},
where the sum is over all the poles of f(z).
[Hint. Consider the integral f(-2)-¹ f(2)dz = f₁ ep−1) ¹(-2) f(z)dz, where I is a suitable
contour.]](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F88e1e2e4-888b-4182-8c02-fd46dda7f6b1%2F645196c7-5a4d-4be3-a17c-69a409b66a28%2Fo4cg4jl_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Let f(z) be a rational function with no poles on the positive real axis, and suppose that
lim z f(z) = lim zºf(z) = 0.
z→0
Z→∞
Show that
[² x²-1¹ f(x) dx =
XP-
π
sin p
Res{(-2)-¹1f(z)},
where the sum is over all the poles of f(z).
[Hint. Consider the integral f(-2)-¹ f(2)dz = f₁ ep−1) ¹(-2) f(z)dz, where I is a suitable
contour.]
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