Let F(x,y): "x is friend with y", N(x): "x is funny", W(x): "x is wise" R(x): "x is fair". The domain for x and y is the set of all persons. Select the symbolic (s) of : "All funny persons are friend with all not wise and not fair persons" ONone of all the proposed answers O 3x Vy N(x) ^ ¬w(y) ^ ¬N(y)→F(x,y) Ox Vy N(x) A ¬w(y) A ¬N(y)→F(x,y) Ox 3y N(x) A¬w(y) A¬N(y)→F(x,y) O vx Vy -(N(x) ^ ¬W(y)) v N(y) v F(x,y)
Let F(x,y): "x is friend with y", N(x): "x is funny", W(x): "x is wise" R(x): "x is fair". The domain for x and y is the set of all persons. Select the symbolic (s) of : "All funny persons are friend with all not wise and not fair persons" ONone of all the proposed answers O 3x Vy N(x) ^ ¬w(y) ^ ¬N(y)→F(x,y) Ox Vy N(x) A ¬w(y) A ¬N(y)→F(x,y) Ox 3y N(x) A¬w(y) A¬N(y)→F(x,y) O vx Vy -(N(x) ^ ¬W(y)) v N(y) v F(x,y)
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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this question is being solved wrong i believe please solve
Transcribed Image Text:QUESTION 1
Let F(x,y): "x is friend with y", N(x): "x is funny", W(x): "x is wise",
R(x): "x is fair". The domain for x and y is the set of all persons.
Select the symbolic (s) of :
"All funny persons are friend with all not wise and not fair persons"
O None of all the proposed answers
U 3xVy N(x)^ ¬w(y) A ¬N(y)→F(x,y)
Vy N(x)A ¬w(y) ^ ¬N(y)→F(x,y)
Ay N(x)A¬w(y) A ¬N(y)→F(x,y)
O vx Vy -(N(x) A ¬w(y)) v N(y) v F(x,y)
QUESTION 2
Expert Solution
Step 1
The quantifiers are "there exist" and "for all".
If only some elements are used, then the quantifier "there exist" is used. If all the elements are used, then the quantifier "for all" is used.
The connectives are "and()", or(),"not()", "implies()".
The symbols can be connected using these connectives.
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