Let f(x) be a function with the following properties: f(1) = 2, ƒ' (1) = 4, ƒ” (1) = What is the second degree Taylor polynomial centered around a = 1 for this function O 2 + 4x + 12x² O 2 + 4(x - 1) + 12(x − 1)² O 2 + 4x + 6x² O 2 + 4(x - 1) + 6(x − 1)² O 2+2x+4x² O2+2(æ −1)+4( −1)2 O None of the above

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A: Solution: Consider the given f(x) is a third-degree polynomial that is f(x) = ax3 + bx2 + cx…

Q: ose P(x) is a polynomial satisfying - P(5) = - 5 - P'(5) = - 305 - P''(5) = – 156 - P(3) (5) = - 414…

A: Note- Since you have posted a question with multiple sub-parts, we will solve first three sub-parts…

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A: To find the equation of the given graph of function f(x) :-

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Q: 1) Let f(x) = e2* Find 3rd Maclaurin Polynomial for f(x)

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Q: Q3: Factorize f (x) = 2x* + x³ + 2x + 4 € Z5[x] as a polynomials product to irreducible over Z5?

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Q: of A, B, and C.

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A: Please see the answer below.

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A: We can check for the values of p(x) :

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Q: The Maclaurin polynomial of degree 4 for the function f(x) = cos(x) is %3D

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Q: f(0) =0, f(1) = 38, f(2) =16, f(-2)=-16, f(-1)=-38 f'(-2) = f"(-1) = f'(1)= f'(2)=0 f'(x)> 0 for x…

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Q: 8. The graph for the polynomial corresponds to the polynomial function given by: a. f(x)=x' +2x²…

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