Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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let f(x) be a function such that its derivative is given by: f'(x)=5(x-1)^2(x-2)^3(x-3)^4. which statement is true about the function f(x)?
![### Analyzing the Derivative of a Function
#### Given Problem
Let \( f(x) \) be a function such that its derivative is given by:
\[ f'(x) = 5(x-1)^2 (x-2)^3 (x-3)^4. \]
Which statement is true about the function \( f(x) \)?
- \(\bigcirc \) It has three local max or local min at \( x = 1, x = 2, \) and \( x = 3 \)
- \(\bigcirc \) It has a local min at \( x = 2 \)
- \(\bigcirc \) It has a local min at \( x = 3 \)
- \(\bigcirc \) It has no local max nor local min
- \(\bigcirc \) None of the above
#### Detailed Analysis
To determine the local extrema of \( f(x) \), we need to analyze its derivative \( f'(x) \).
1. **Critical Points:**
- The derivative \( f'(x) = 0 \) at \( x = 1, 2, 3 \).
2. **Behavior of \( f'(x) \) Based on its Factors:**
- **At \( x = 1 \):** The factor \((x-1)^2\) makes \( f'(x) \) equal zero. Since the power is even (2), the sign of \( f'(x) \) does not change around \( x = 1 \). This suggests that \( x = 1 \) is more likely a point of inflection rather than a local maximum or minimum.
- **At \( x = 2 \):** The factor \((x-2)^3\) makes \( f'(x) \) equal zero. Since the power is odd (3), the sign of \( f'(x) \) changes around \( x = 2 \). This indicates that \( x = 2 \) is a local extremum. Given that the factor is raised to an odd power greater than 1, which affects the steepness at that point, it suggests a local minimum.
- **At \( x = 3 \):** The factor \((x-3)^4\) makes \( f'(x) \) equal zero. Since the power is even (4),](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F15ebcc29-b4c9-4b75-827b-e8d2ccef5d21%2F34e1d76b-c5d9-4392-ab0b-b655aa5b6f28%2Fnofl968.jpeg&w=3840&q=75)
Transcribed Image Text:### Analyzing the Derivative of a Function
#### Given Problem
Let \( f(x) \) be a function such that its derivative is given by:
\[ f'(x) = 5(x-1)^2 (x-2)^3 (x-3)^4. \]
Which statement is true about the function \( f(x) \)?
- \(\bigcirc \) It has three local max or local min at \( x = 1, x = 2, \) and \( x = 3 \)
- \(\bigcirc \) It has a local min at \( x = 2 \)
- \(\bigcirc \) It has a local min at \( x = 3 \)
- \(\bigcirc \) It has no local max nor local min
- \(\bigcirc \) None of the above
#### Detailed Analysis
To determine the local extrema of \( f(x) \), we need to analyze its derivative \( f'(x) \).
1. **Critical Points:**
- The derivative \( f'(x) = 0 \) at \( x = 1, 2, 3 \).
2. **Behavior of \( f'(x) \) Based on its Factors:**
- **At \( x = 1 \):** The factor \((x-1)^2\) makes \( f'(x) \) equal zero. Since the power is even (2), the sign of \( f'(x) \) does not change around \( x = 1 \). This suggests that \( x = 1 \) is more likely a point of inflection rather than a local maximum or minimum.
- **At \( x = 2 \):** The factor \((x-2)^3\) makes \( f'(x) \) equal zero. Since the power is odd (3), the sign of \( f'(x) \) changes around \( x = 2 \). This indicates that \( x = 2 \) is a local extremum. Given that the factor is raised to an odd power greater than 1, which affects the steepness at that point, it suggests a local minimum.
- **At \( x = 3 \):** The factor \((x-3)^4\) makes \( f'(x) \) equal zero. Since the power is even (4),
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