Let f(x) and g(x) be functions. Prove, using contradiction method, that if f(g(x)) is one-to-one, then g(x) is one-to-one.That is, suppose that g(x) were not one-to-one and derive that f(g(x)) cannot be one-to-one.
Let f(x) and g(x) be functions. Prove, using contradiction method, that if f(g(x)) is one-to-one, then g(x) is one-to-one.That is, suppose that g(x) were not one-to-one and derive that f(g(x)) cannot be one-to-one.
Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
18th Edition
ISBN:9780079039897
Author:Carter
Publisher:Carter
Chapter9: Quadratic Functions And Equations
Section9.9: Combining Functions
Problem 50HP
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Let f(x) and g(x) be functions. Prove, using contradiction method,
that if f(g(x)) is one-to-one, then g(x) is one-to-one.That is, suppose that g(x) were not one-to-one and derive that f(g(x)) cannot be one-to-one.
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