Let f(x) = 39 - The slope of the tangent line to the graph of f (x) at the point (-6, 3) is The equation of the tangent line to the graph of f (x) at (-6, 3) is y = mx + b for m and b Hint: the slope is given by the derivative at x = -6, ie. ƒ (−6 + h) − ƒ (−6) h lim h→0

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Q: y = 3x?+1 ; (0,1)

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Q: a).Find x value where the graph has a horizontal tangent line. f(x) = x^3 + x Using the fact that…

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Q: Find the equation of the tangent line (in Slope-Intercept Form) at the given point. Function: h(t) =…

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Q: If f(x)=x²+ax+b and the slope of tangent at x= -1 is 4 and the curve passes the point (2,4) Find…

A: I have stated the used formula in the solution