Let f(x) = √38 - x The slope of the tangent line to the graph of f(x) at the point (2,6) is The equation of the tangent line to the graph of f(x) at (2,6) is y = mx + b for m = and b = Hint: the slope at x = 2 is given by f(2+h)-f(2) h = lim h→0 m =

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
Question
Let f(x) = √38 - x
The slope of the tangent line to the graph of f(x) at the point (2,6) is
The equation of the tangent line to the graph of f(x) at (2,6) is y = mx + b for
m =
and
b =
Hint: the slope at x = 2 is given by
ƒ(2+h)-f(2)
h
m = : lim
h→0
Transcribed Image Text:Let f(x) = √38 - x The slope of the tangent line to the graph of f(x) at the point (2,6) is The equation of the tangent line to the graph of f(x) at (2,6) is y = mx + b for m = and b = Hint: the slope at x = 2 is given by ƒ(2+h)-f(2) h m = : lim h→0
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