Let f(x) = 2x³ – 0.0064x² – 1.5x + 1 i. Indicate that f(x) = 0 has a root in the interval [-3, 0] with |bo – aol = 1. ii. Examine which method is less iteration (i) to find the root in Q1 (i) by using Secant and Newton-Raphson method. Stop iteration if |f(x;)| < 0.0005 or i > 7.

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter5: Inverse, Exponential, And Logarithmic Functions
Section5.6: Exponential And Logarithmic Equations
Problem 1E
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Let f(x) = 2x3 – 0.0064x? – 1.5x +1
i.
Indicate that f(x) = 0 has a root in the interval [-3, 0] with |bo – aol = 1.
ii.
Examine which method is less iteration (i) to find the root in Q1 (i) by
using Secant and Newton-Raphson method. Stop iteration if |f(x;)| <
0.0005 or i > 7.
Transcribed Image Text:Let f(x) = 2x3 – 0.0064x? – 1.5x +1 i. Indicate that f(x) = 0 has a root in the interval [-3, 0] with |bo – aol = 1. ii. Examine which method is less iteration (i) to find the root in Q1 (i) by using Secant and Newton-Raphson method. Stop iteration if |f(x;)| < 0.0005 or i > 7.
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