Let f(x) = (2a² – 8) (5æ + 8) 13 %3D f'(x)

Q: If f(x) = (6x² – 2) (5æ + 6), find: %3D f'(x) = %3D f'(3) =

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Q: (a) / (2.x4 + Vx3 + 4e* + + 8) dx - (b) / = x3 + 3x – 4 dx - x2 (c) (x + 4)(x³ – 9) dx .3 -

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Q: Let h(x) = 3x² + x -x² + 3x - 3 what is h' (2)?

A: We need to find out h'(2).

Q: Given f(x) = In(- 4e" – 13), f'(x) = %3D

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Q: Integrate S(x-4)(x²-8x+12} dx

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Q: 3x + 7 If f(x) = find: %3D 3x + 5 f'(x) = %3D f'(1) =

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Q: Find f. f"(x) = 6 + 6x + 24x2, f(0) = 2, f(1) = 12 f(x) =

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Q: f'(x) = 6Vx ; f(1) = 7,

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Q: d/dx of F(x)=2X-21

A: ddx(2x-21)=?

Q: lIf 90 +9f(x) + x²(F(x))* = 0 and f(3) = -2, find f'(3). f'(3) = %3D

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Q: 6x + 6 If f(x) = find: %3D 4x + 4' f'(z) = f'(3) =

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Q: Find f such that f'(x) = 8x + 9x-2 and f(0) =5. %3D f(x) =| %3D

A: Concept : if f'(x) is known for finding f(x) we need to integrate f'(x) with respective x…

Q: If f(x) = x2/(4 + x), find f "(2). f "(2) =

A: f(x) = x2 /(4+x)  f'(x) = [(4+x)(2x) - x2(1)] / (4+x)2  = (8x+2x2 - x2)/(4+x)2 = (8x+x2)/(4+x)2…

Q: Find f such that f'(x)= 8x-9, f(6) = 0. f(x) = b

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Q: Find f. (x + 1) f'(x) = (1) = 3 %3D f(x) =

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Q: The function f(x)=(1/(x+1))+4 is decreasing on what interval(s)?

A: Consider the function  fx=1x+1+4

Q: If f(x) = (2x + 1) (x - 3)°, then f'(2) = %3D

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Q: 9. (x+ 3)(x – 6) = 10 %3D

A: Our Aim is to solve the equation given below for x:-(x+3)(x-6)=10 -(i)

Q: If f(4) = 3 and f'(x) 2 3 for 4 s xs 9, how small can f(9) possibly be? (9) 2

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Q: If f(x) = x²/(1 + x), find f "(1). f"(1) = %3D %3D

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Q: Let

A: Explanation and solution is given below....