Let FLOOR(1)+ FLOOR(1/2)+ FLOOR(1/3) + ... + FLOOR(1/n) = CEILING(0/1) + CEILING(1/2)+ CEILING(2/3) + ... + CEILING(1 - (1/n)) be given. Then, a value of n that satisfies the previous equation is Answer:

Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
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Question 8

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Let
FLOOR(1)+ FLOOR(1/2)+ FLOOR(1/3) + ... + FLOOR(1/n) = CEILING(0/1)
+ CEILING(1/2)+ CEILING(2/3) + ... + CEILING(1 - (1/n))
be given.
Then, a value of n that satisfies the previous equation is
Answer:
Transcribed Image Text:Let FLOOR(1)+ FLOOR(1/2)+ FLOOR(1/3) + ... + FLOOR(1/n) = CEILING(0/1) + CEILING(1/2)+ CEILING(2/3) + ... + CEILING(1 - (1/n)) be given. Then, a value of n that satisfies the previous equation is Answer:
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