Let f:[0,7] be defined by f(x) = x2-3x+1. Let a(x) = 3I(x-1) + 2I(x-4) + I(x-5) + 4I(x-6), where I is the unit step function. Comute the integral from 0 to 7 of f d(a).
Let f:[0,7] be defined by f(x) = x2-3x+1. Let a(x) = 3I(x-1) + 2I(x-4) + I(x-5) + 4I(x-6), where I is the unit step function. Comute the integral from 0 to 7 of f d(a).
Let f:[0,7] be defined by f(x) = x2-3x+1. Let a(x) = 3I(x-1) + 2I(x-4) + I(x-5) + 4I(x-6), where I is the unit step function. Comute the integral from 0 to 7 of f d(a).
Let f:[0,7] be defined by f(x) = x2-3x+1. Let a(x) = 3I(x-1) + 2I(x-4) + I(x-5) + 4I(x-6), where I is the unit step function. Comute the integral from 0 to 7 of f d(a).
With differentiation, one of the major concepts of calculus. Integration involves the calculation of an integral, which is useful to find many quantities such as areas, volumes, and displacement.
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