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Let f0) - cost). Then T,6) cenered at a = is---)---)* --)° * ). 2 48 Use T(x), at an appropriate x-value, rounded to five decimal places to estimate cos(35°).

Let f0) - cost). Then T,6) cenered at a = is---)---)* --)° * ). 2 48 Use T(x), at an appropriate x-value, rounded to five decimal places to estimate cos(35°).

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Let \( f(x) = \cos(x) \). Then \( T_4(x) \) centered at \( a = \frac{\pi}{6} \) is \[ \frac{\sqrt{3}}{2} - \frac{1}{2}(x - \frac{\pi}{6}) - \frac{\sqrt{3}}{4}(x - \frac{\pi}{6})^2 + \frac{1}{12}(x - \frac{\pi}{6})^3 + \frac{\sqrt{3}}{48}(x - \frac{\pi}{6})^4. \] Use \( T_4(x) \), at an appropriate \( x \)-value, rounded to five decimal places to estimate \(\cos(35^\circ)\). [Enter answer in the text box provided.]
Transcribed Image Text:Let \( f(x) = \cos(x) \). Then \( T_4(x) \) centered at \( a = \frac{\pi}{6} \) is \[ \frac{\sqrt{3}}{2} - \frac{1}{2}(x - \frac{\pi}{6}) - \frac{\sqrt{3}}{4}(x - \frac{\pi}{6})^2 + \frac{1}{12}(x - \frac{\pi}{6})^3 + \frac{\sqrt{3}}{48}(x - \frac{\pi}{6})^4. \] Use \( T_4(x) \), at an appropriate \( x \)-value, rounded to five decimal places to estimate \(\cos(35^\circ)\). [Enter answer in the text box provided.]
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