Let ƒ (x) = x³ – 5x² – 8 and let g be the inverse of f (i.e. g (x) = f -1 (x).

Q: (x + 1) f' (x) = f(1) = 5 x,

A: Solution is given below:

Q: Find f f ''(x) = 8 + 6x + 36x2, f(0) = 2, f (1) = 13

A: *to find:- f(x).

Q: Find f. f'(x)  = x-1/3    ,f(1)  =1, f(-1)  = -1

A: To find f(x) we integrate f'(x) C=integrating constant

Q: Find f. f'(X) = Vx(6 + 10x), f(1) = 11 f(x) =

A:

Q: Find f'(a) for f'(a) = f(x): = -9 √2 - 4x

A:

Q: 6. 2х — 7 H(x) .2 х? + 3,

A: We will use Chain rule and Division rule of derivative

Q: Find f'(0) for f(x) x = 0. 0,

A:

Q: For f(x) = 8 find f'(x). f'(x) =D

A: Explanation of the answer is as follows

Q: Find  f '(a). f(x) =    1 − 4x

A:

Q: Find f. f ''(t) = 9/sqt t,    f(4) = 29,    f '(4) = 9

A:

Q: Find f. f ''(t) = 9/ squareroot t,    f(4) = 31,    f '(4) = 12

A:

Q: find f'(a) f(t) = 1/(t2+7)

A:

Q: Find f. f"(x) = Vx(6 + 10x), f(1) = 9 f(x) =

A:

Q: Find f'(x) and f'(c). Function Value of c f(x) = (x³ + 2x)(5x³ + 5x – 4) c = 0 f'(x) = f'(c) =

A: Given fx=x5+2x5x5+5x-4c=0

Q: Find f'(a). f'(a) = f(x) = 2x² - 3x + 1

A:

Q: Find f'(a). f'(a) = f(x) = √√/2 - 6x

A: The function is The aim is to find the value of f′(a)

Q: Find f'(a). f(x) = V1 – 2x %3D |

A:

Q: Find  f'(a)

A: Here given function as ft=2t+1t+3

Q: If f(x) = (5x +6) find f'(x). Find f'(3).

A: topic - derivative of a function

Q: Find f. f"(x)  =8  x3 + 5   , f(1)   =  0 , f'(1)  =8

A: It is given that, f''x=8x3+5,  f1=0, f'1=8.   Integrate the function f''x=8x3+5 as follows".…

Q: Find f'(9) if f(x) = 7x² +6x + 2 √x f'(9)=

A: we know, ddx(xn)=nx(n-1) for any real n

Q: Obtain f'(7) f(x)= x / x^2+3

A: Given             f(x)= x / x^2+3

Q: Find f. f ''(x) = −2 + 36x − 12x2,    f(0) = 5,    f '(0) = 18

A:

Q: Find f'(a). f(x) = 3x 3x + 2 3x² f'(a) =

A:

Q: Find f. f ''(x) = −2 + 12x − 12x2,    f(0) = 9,    f '(0) = 18   f(x) =

A:

Q: Find f'(a). ƒ'(a) = f(x) = V 2 - 2x

A: Given query is to find indicated derivative.

Q: Find f '(a) f(t) = (8t + 34)/(t + 9) f '(a) =

A: