Let f be the function defined as follows y= f(x) = 5x^2 - 6x +5 (a) Find the differential of f. dy = (b) Use your result from part (a) to find the approximate change in y if x changes from 2 to 1.97. (round to two decimal places) dy= (c) find the actual change in y if x changes from 2 to 1.97 and compare your result with that obtained in part (b). (round to two decimal places) delta y =
Let f be the function defined as follows y= f(x) = 5x^2 - 6x +5 (a) Find the differential of f. dy = (b) Use your result from part (a) to find the approximate change in y if x changes from 2 to 1.97. (round to two decimal places) dy= (c) find the actual change in y if x changes from 2 to 1.97 and compare your result with that obtained in part (b). (round to two decimal places) delta y =
Let f be the function defined as follows y= f(x) = 5x^2 - 6x +5 (a) Find the differential of f. dy = (b) Use your result from part (a) to find the approximate change in y if x changes from 2 to 1.97. (round to two decimal places) dy= (c) find the actual change in y if x changes from 2 to 1.97 and compare your result with that obtained in part (b). (round to two decimal places) delta y =
Let f be the function defined as follows
y= f(x) = 5x^2 - 6x +5
(a) Find the differential of f.
dy =
(b) Use your result from part
(a) to find the approximate change in y if x changes from 2 to 1.97. (round to two decimal places)
dy=
(c) find the actual change in y if x changes from 2 to 1.97 and compare your result with that obtained in part (b). (round to two decimal places)
delta y =
With integration, one of the major concepts of calculus. Differentiation is the derivative or rate of change of a function with respect to the independent variable.
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