Let f be a function on an interval I and let ₁ and 2 be any two points in I. Then if f (x₁) > f (x₂) whenever x₁ < x2, then f is said to be on I.
Let f be a function on an interval I and let ₁ and 2 be any two points in I. Then if f (x₁) > f (x₂) whenever x₁ < x2, then f is said to be on I.
Chapter3: Functions
Section3.7: Inverse Functions
Problem 6SE: Show that the function fx)=ax is its own inverse for all real numbers a.
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![Let f be a function on an interval I and let ₁ and 2 be any two points in I. Then if
f (x₁) > f (x₂) whenever ₁ < x2, then f is said to be
on I.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fbc60b518-9598-40b1-bf87-914c29da14e8%2Fe8c94d50-ff6e-4ad8-aa34-a16c752a0af6%2F8v1xyq_processed.png&w=3840&q=75)
Transcribed Image Text:Let f be a function on an interval I and let ₁ and 2 be any two points in I. Then if
f (x₁) > f (x₂) whenever ₁ < x2, then f is said to be
on I.
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