Let F = (5t + 1) i + sin(t) j+ 5tk Find F' (1), F" (t) and F" (t) (1) F'(1) = (2) F" (1) = (3) F" (t) =

Q: Find f. f'(t) 8 cos(t) + sec?(t), -7/2 <t < a/2, f(a/3) = 5 f(t) =

A: Given

Q: 3 Find f'(x)given f(x) = x/x – 4x – 7x %3D

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Q: Find f(x), where f'(x) = sin(x)+ cos(x) + 1 and f(r) = 2. %3D %3D

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Q: Find f'(z) of f(z) = 3πi.

A: Compare the given function f(z) = 3πi. with f(z)=u(x,y)+i v(x,y) So,  u(x,y) =0 and v(x,y) = 3π

Q: x²y" + 3ry – 24y = 0, y(1) = -8, y'(1) = –7. y =

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Q: Let f (x) = 2x4 + 2x3 + 2x2 + 5x + 2. Fill in the missing coefficients for the derivative of f: x* +…

A: Given that :-  f is function of x f(x) = 2x⁴ + 2x³ + 2x² + 5x + 2 * We have to find  f '(x)   For…

Q: Find y as a function of t if 5184y" – 1584y + 121y = 0, - y(0) = 6, y'(0) = 3. y =

A: We have to find the general solution of the given problem.

Q: Use the rule for square roots: f'(x) 2/ F(x) V F(x) to find the following derivatives (quickly d V…

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Q: 3. Find the derivatives: 3x3-4 a) f (x) = b) y = (x2 + 6x + 2) (+ Vx5 + 3) DO NOT SIMPLIFY 2x²+3 c)…

A: a) Use quotient rule of derivative and find the derivatives of above function.

Q: f(t)=5 sec²(7 Tt – 3)

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Q: Find f if f'''(x)=cosx,f(0)=1,f(0)=1,f'(0)=2,f''(0)=3

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Q: Find y as a function of a if y(1)9, y'(1) = -5. y = x²y" - 15xy' + 64y = x²,

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Q: Find f. f(t) = f'(t) sec(t) (sec(t) + tan(t)), -2-√2 x Need Help? Read It Watch It - 1/2 < t < 1/₁ (…

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Q: Let f(x) = 5x4 - -1/2+8√x-3. (a) Find f'(x). (b) Find an equation for the tangent line to the graph…

A: Given that            function f(x) = 5x4-2x2+8x-3     Now             f'(x)    =  ddx5x4-2x2+8x-3…

Q: Find f f(0) = 2, f '(0) = 1 f "(0) sin 0 + cos 0, f(0)

A: Given that

Q: Can you find f

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Q: Find f. f'(t) = sec(t)(sec(t) + tan(t)), f(t) = - 1/2 <²<= // ¹ ( ² ) = -3

A: Given that, f't=sectsect+tant, -π2&lt;t&lt;π2, fπ4=-3 We have to find the function ft

Q: Let f (t) = et sin 7t Part (a) Find L{f (t)} Part (b) Find L{f' (t)}

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Q: Find f. f'(t) = sec(t)(sec(t) + tan(t)), = -1 f(t) =

A: Given that: f'(t)=sect(sect+tant),    -π2&lt;t&lt;π2, fπ4=-1

Q: 2) s(t)=5e" (3r -51)

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Q: f(x) = cos x + 3, [0, 27], midpoint

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