Let f(¹) = √2 +2. Since f(x) is differentiable on [-2, 7], by the Mean Value Theorem, we know there exists at least one c in the open interval (-2, 7) such that f'(c) is equal to the mean slope on the interval [ – 2,7]. This function has one such c. Find it using calculus. C = Now give the graphical representation of the Mean Value Theorem in this case: To do this, graph these three things: 1. f(1) = √2+2 2. The secant line through (-2, 0) and (7,3) and 3. The tangent line at the point, c, such that the tangent line is parallel to the secant line.