Let F = < xyz, xy, xʻyz > . Use Stokes' Theorem to evaluate curlF · d5, where S consists of the top and the four sides (but not the bottom) of the cube with one corner at (-1,-1,-1) and the diagonal corner at (4,4,4). Hint: Use the fact that if S1 and S2 share the same boundary curve C that curlF · d5 = | F - . dī curlF · dS S2

Advanced Engineering Mathematics
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Chapter2: Second-order Linear Odes
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### Vector Field and Stokes' Theorem

Let \( \mathbf{F} = \langle xyz, xy, x^2yz \rangle \).

Use Stokes' Theorem to evaluate
\[ \iint_S \text{curl} \, \mathbf{F} \cdot d\mathbf{S}, \]
where \( S \) consists of the top and the four sides (but not the bottom) of the cube with one corner at \((-1, -1, -1)\) and the diagonal corner at \((4, 4, 4)\).

There is an empty space below this statement that is likely meant for student input or solution steps.

#### Hint

Use the fact that if \( S_1 \) and \( S_2 \) share the same boundary curve \( C \), then
\[ \iint_{S_1} \text{curl} \, \mathbf{F} \cdot d\mathbf{S} = \oint_C \mathbf{F} \cdot d\mathbf{r} = \iint_{S_2} \text{curl} \, \mathbf{F} \cdot d\mathbf{S}. \]

This suggests using the equivalence of the surface integrals of the curl of \( \mathbf{F} \) over different surfaces sharing the same boundary to simplify calculations.

### Explanation of Concepts

**Stokes' Theorem:**

Stokes' Theorem relates a surface integral over surface \( S \) to a line integral over the boundary curve \( C \) of that surface.

\[ \iint_S \text{curl} \, \mathbf{F} \cdot d\mathbf{S} = \oint_C \mathbf{F} \cdot d\mathbf{r}. \]

This theorem is useful for converting a difficult surface integral into a more manageable line integral, or vice versa.

**Application to the Problem:**

Given the specific vector field \( \mathbf{F} = \langle xyz, xy, x^2yz \rangle \) and the surface \( S \) that is a cube excluding the bottom face, the problem directs you to use Stokes' Theorem. The hint suggests that the boundary curve \( C \) of the surface \( S \) can be used to simplify the evaluation of the integral.

**Diagrams or Graphs:**
Transcribed Image Text:### Vector Field and Stokes' Theorem Let \( \mathbf{F} = \langle xyz, xy, x^2yz \rangle \). Use Stokes' Theorem to evaluate \[ \iint_S \text{curl} \, \mathbf{F} \cdot d\mathbf{S}, \] where \( S \) consists of the top and the four sides (but not the bottom) of the cube with one corner at \((-1, -1, -1)\) and the diagonal corner at \((4, 4, 4)\). There is an empty space below this statement that is likely meant for student input or solution steps. #### Hint Use the fact that if \( S_1 \) and \( S_2 \) share the same boundary curve \( C \), then \[ \iint_{S_1} \text{curl} \, \mathbf{F} \cdot d\mathbf{S} = \oint_C \mathbf{F} \cdot d\mathbf{r} = \iint_{S_2} \text{curl} \, \mathbf{F} \cdot d\mathbf{S}. \] This suggests using the equivalence of the surface integrals of the curl of \( \mathbf{F} \) over different surfaces sharing the same boundary to simplify calculations. ### Explanation of Concepts **Stokes' Theorem:** Stokes' Theorem relates a surface integral over surface \( S \) to a line integral over the boundary curve \( C \) of that surface. \[ \iint_S \text{curl} \, \mathbf{F} \cdot d\mathbf{S} = \oint_C \mathbf{F} \cdot d\mathbf{r}. \] This theorem is useful for converting a difficult surface integral into a more manageable line integral, or vice versa. **Application to the Problem:** Given the specific vector field \( \mathbf{F} = \langle xyz, xy, x^2yz \rangle \) and the surface \( S \) that is a cube excluding the bottom face, the problem directs you to use Stokes' Theorem. The hint suggests that the boundary curve \( C \) of the surface \( S \) can be used to simplify the evaluation of the integral. **Diagrams or Graphs:**
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