Let C(x) be the predicate " is a comedian", and let F(x) funny." Match the statements below on the left to their equivalent English translations on the right. DOOD Vx(F(x) ^ C(x)) Va (F(x) → C(x)) 3x(F(x) V-C(x)) Vx-(F(x) ^ C(x)) 3x (F(x)^-C(x)) Yr (C(x) → ¬F(x)) 1. All funny people are comedians. Not all funny people are comedians. 2. 3. No comedian is funny. 4. Everyone is a funny comedian. It is not the case that everyone is a funny comedian. 6. No one is a funny comedian. 5.
Let C(x) be the predicate " is a comedian", and let F(x) funny." Match the statements below on the left to their equivalent English translations on the right. DOOD Vx(F(x) ^ C(x)) Va (F(x) → C(x)) 3x(F(x) V-C(x)) Vx-(F(x) ^ C(x)) 3x (F(x)^-C(x)) Yr (C(x) → ¬F(x)) 1. All funny people are comedians. Not all funny people are comedians. 2. 3. No comedian is funny. 4. Everyone is a funny comedian. It is not the case that everyone is a funny comedian. 6. No one is a funny comedian. 5.
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Transcribed Image Text:Let C(x) be the predicate " is a comedian", and let F(x) be the predicate" is
funny."
Match the statements below on the left to their equivalent English translations on
the right.
DOD
Vx(F(x) ^ C(x))
Vx (F(x) → C(x))
3x(F(x) V-C(x))
Vx-(F(x) ^ C'(x))
3x (F(x)^-C(x))
Vx (C(x)→-F(x))
1. All funny people are comedians.
Not all funny people are
comedians.
2.
3. No comedian is funny.
4. Everyone is a funny comedian.
It is not the case that everyone is a
funny comedian.
6. No one is a funny comedian.
5.
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