Let C'(x) be the cost (in dollars) of producing units of a product per day. Suppose C(99) = 90 and C' (99)=-6. Estimate the cost of producing 100 items per day.
Let C'(x) be the cost (in dollars) of producing units of a product per day. Suppose C(99) = 90 and C' (99)=-6. Estimate the cost of producing 100 items per day.
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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![**Problem Statement:**
Let \( C(x) \) be the cost (in dollars) of producing \( x \) units of a product per day. Suppose \( C(99) = 90 \) and \( C'(99) = -6 \). Estimate the cost of producing 100 items per day.
**Solution:**
To estimate the cost of producing 100 items, we can use the information given and apply the concept of linear approximations or differentials. The derivative \( C'(99) \) gives us the rate at which the cost is changing at the production level of 99 units.
Given:
- \( C(99) = 90 \)
- \( C'(99) = -6 \)
We can approximate \( C(100) \) using the formula for linear approximation:
\[ C(100) \approx C(99) + C'(99) \times (100 - 99) \]
Substituting the known values:
\[ C(100) \approx 90 + (-6) \times 1 \]
\[ C(100) \approx 90 - 6 \]
\[ C(100) \approx 84 \]
Therefore, the estimated cost of producing 100 items per day is approximately $84.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F2ee05961-48f0-4164-984e-730a8b15f9ee%2F9a11108c-f49f-4e62-b3a0-8b690b1f08f8%2F4vrnbqs_processed.png&w=3840&q=75)
Transcribed Image Text:**Problem Statement:**
Let \( C(x) \) be the cost (in dollars) of producing \( x \) units of a product per day. Suppose \( C(99) = 90 \) and \( C'(99) = -6 \). Estimate the cost of producing 100 items per day.
**Solution:**
To estimate the cost of producing 100 items, we can use the information given and apply the concept of linear approximations or differentials. The derivative \( C'(99) \) gives us the rate at which the cost is changing at the production level of 99 units.
Given:
- \( C(99) = 90 \)
- \( C'(99) = -6 \)
We can approximate \( C(100) \) using the formula for linear approximation:
\[ C(100) \approx C(99) + C'(99) \times (100 - 99) \]
Substituting the known values:
\[ C(100) \approx 90 + (-6) \times 1 \]
\[ C(100) \approx 90 - 6 \]
\[ C(100) \approx 84 \]
Therefore, the estimated cost of producing 100 items per day is approximately $84.
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