Let C be the intersection curve of the paraboloid z = x2 − y2/2 with the cylinder x2 + y2 = 1, traveled counterclockwise when viewed from above (that is, its XY projection travels counterclockwise). Let I = (image 1), with F⃗ (x, y, z) = (3xy/2,3x2/4 + xz, −xy/2). When applying Stokes' Theorem to calculate the line integral I, the resulting double integral corresponds to: (image 2)
Let C be the intersection curve of the paraboloid z = x2 − y2/2 with the cylinder x2 + y2 = 1, traveled counterclockwise when viewed from above (that is, its XY projection travels counterclockwise). Let I = (image 1), with F⃗ (x, y, z) = (3xy/2,3x2/4 + xz, −xy/2). When applying Stokes' Theorem to calculate the line integral I, the resulting double integral corresponds to: (image 2)
Let C be the intersection curve of the paraboloid z = x2 − y2/2 with the cylinder x2 + y2 = 1, traveled counterclockwise when viewed from above (that is, its XY projection travels counterclockwise). Let I = (image 1), with F⃗ (x, y, z) = (3xy/2,3x2/4 + xz, −xy/2). When applying Stokes' Theorem to calculate the line integral I, the resulting double integral corresponds to: (image 2)
Let C be the intersection curve of the paraboloid z = x2 − y2/2 with the cylinder x2 + y2 = 1, traveled counterclockwise when viewed from above (that is, its XY projection travels counterclockwise).
Let I = (image 1), with F⃗ (x, y, z) = (3xy/2,3x2/4 + xz, −xy/2). When applying Stokes' Theorem to calculate the line integral I, the resulting double integral corresponds to: (image 2)
Transcribed Image Text:I= Se F. dr, con F(x, y, z) =
3zy 37
(, +cz, -).
4
With differentiation, one of the major concepts of calculus. Integration involves the calculation of an integral, which is useful to find many quantities such as areas, volumes, and displacement.
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