Let C be the curve of intersection of the spheres x² + y2 + z² = 83 and (x - 2)² + (y-2)² + z² = 83. Find the parametric equations of the tangent line to C at P = (1, 1,9). It is known that if the intersection of two surfaces F(x, y, z) = 0 and G(x, y, z) = 0 is a curve C and P is a point on C, then the vector v = VFp x VGp is a direction vector for the tangent line to C at P. (Use symbolic notation and fractions where needed. Enter your answers as functions of parameter t in a form r(t) = (x(t), y(t), z(t)) = ro + vt, where ro is the corresponding coordinate of point P.)

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Chapter2: Second-order Linear Odes
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**Parametric Equations of the Tangent Line at the Intersection of Spheres**

Let \( C \) be the curve of intersection of the spheres \( x^2 + y^2 + z^2 = 83 \) and \( (x-2)^2 + (y-2)^2 + z^2 = 83 \). 

We are asked to find the parametric equations of the tangent line to \( C \) at \( P = (1, 1, 9) \).

It is known that if the intersection of two surfaces \( F(x, y, z) = 0 \) and \( G(x, y, z) = 0 \) is a curve \( C \) and \( P \) is a point on \( C \), then the vector \( \mathbf{v} = \nabla F_P \times \nabla G_P \) is a direction vector for the tangent line to \( C \) at \( P \).

**Use symbolic notation and fractions where needed. Enter your answers as functions of parameter \( t \) in a form \(\mathbf{r}(t) = \langle x(t), y(t), z(t) \rangle = \mathbf{r_0} + \mathbf{v}t\), where \(\mathbf{r_0}\) is the corresponding coordinate of point \( P \).**

### Solution:
Given:
- \( x^2 + y^2 + z^2 = 83 \)
- \( (x-2)^2 + (y-2)^2 + z^2 = 83 \)
- Point \( P = (1, 1, 9) \)

To find the parametric equations:

1. **Calculate Gradients**
   - Gradient of \( F(x,y,z) \) at \( P \):
     \[
     F(x, y, z) = x^2 + y^2 + z^2 - 83 
     \]
     \[
     \nabla F = \left\langle 2x, 2y, 2z \right\rangle 
     \]

     At point \( P = (1, 1, 9) \):
     \[
     \nabla F_P = \left\langle 2(1), 2(1), 2(9) \right\rangle = \left
Transcribed Image Text:**Parametric Equations of the Tangent Line at the Intersection of Spheres** Let \( C \) be the curve of intersection of the spheres \( x^2 + y^2 + z^2 = 83 \) and \( (x-2)^2 + (y-2)^2 + z^2 = 83 \). We are asked to find the parametric equations of the tangent line to \( C \) at \( P = (1, 1, 9) \). It is known that if the intersection of two surfaces \( F(x, y, z) = 0 \) and \( G(x, y, z) = 0 \) is a curve \( C \) and \( P \) is a point on \( C \), then the vector \( \mathbf{v} = \nabla F_P \times \nabla G_P \) is a direction vector for the tangent line to \( C \) at \( P \). **Use symbolic notation and fractions where needed. Enter your answers as functions of parameter \( t \) in a form \(\mathbf{r}(t) = \langle x(t), y(t), z(t) \rangle = \mathbf{r_0} + \mathbf{v}t\), where \(\mathbf{r_0}\) is the corresponding coordinate of point \( P \).** ### Solution: Given: - \( x^2 + y^2 + z^2 = 83 \) - \( (x-2)^2 + (y-2)^2 + z^2 = 83 \) - Point \( P = (1, 1, 9) \) To find the parametric equations: 1. **Calculate Gradients** - Gradient of \( F(x,y,z) \) at \( P \): \[ F(x, y, z) = x^2 + y^2 + z^2 - 83 \] \[ \nabla F = \left\langle 2x, 2y, 2z \right\rangle \] At point \( P = (1, 1, 9) \): \[ \nabla F_P = \left\langle 2(1), 2(1), 2(9) \right\rangle = \left
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