Let C be the cost function. C'(x) = 3600 + 100x + 2x² (in blue) and let R be the revenue function, R(x) = 500x - 2x² (in red) below. What are the x values where the two functions are equal? Enter your answers with *₁ < #₂: 1.₁= 2. I₂ =

Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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மபு
35000
R(X)
150
Transcribed Image Text:மபு 35000 R(X) 150
Let C be the cost function, C'(x) = 3600 + 100x + 2x² (in blue) and let R be the revenue function, R(x) = 500x – 2x² (in red) below.
What are the x values where the two functions are equal? Enter your answers with #₁ < #2:
1.1=
2. #₂ =
Transcribed Image Text:Let C be the cost function, C'(x) = 3600 + 100x + 2x² (in blue) and let R be the revenue function, R(x) = 500x – 2x² (in red) below. What are the x values where the two functions are equal? Enter your answers with #₁ < #2: 1.1= 2. #₂ =
Expert Solution
Step 1

INTRODUCTION 

Equating functions means setting two functions equal to each other. This is typically done to solve for the value(s) of the independent variable(s) that make the two functions equal. Equating functions can also be used to find the intersection points of two graphs, which represent the values of x where the two functions have the same y-values. These intersection points can be found by setting the two functions equal to each other and then solving for x and then substituting that value of x back into one of the original functions to find the corresponding y-value.

 

Given details:  The cost function C(x) and the revenue function R(x) is given as:

C(x)=3600+100x+2x2R(x)=500x-2x2

To determine:  We have to find the two values of x where the two functions are equal.

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