Let (an) and (bn) be convergent sequences such that lim an = L₁ and lim b,= L₂. Prove, using 71-00 11400 N. e type methods only, that the limit operator is linear and, distributes across products such that lim (a, b) L₁ L₂ 11-00

Calculus: Early Transcendentals
8th Edition
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Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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### Problem Statement

Let \(\{a_n\}\) and \(\{b_n\}\) be convergent sequences such that 
\[ \lim_{{n \to \infty}} a_n = L_1 \]
and 
\[ \lim_{{n \to \infty}} b_n = L_2. \]
Prove, **using \(N, \epsilon \) type methods only**, that the limit operator is linear and distributes across products, such that

\[ \lim_{{n \to \infty}} (a_n \cdot b_n) = L_1 \cdot L_2. \]

### Key Points

- **Convergent Sequences:** Sequences \(\{a_n\}\) and \(\{b_n\}\) converge to \(L_1\) and \(L_2\) respectively.
- **Limit Operator Linearity:** The objective is to show that the limit operator distributes across the product of two convergent sequences using \(N, \epsilon \) methods.

### Methodology

1. **Definitions:**
   - A sequence \(\{a_n\}\) converges to \(L_1\) means for every \(\epsilon > 0\), there exists a positive integer \(N_1\) such that for all \(n \geq N_1\), \(|a_n - L_1| < \epsilon\).
   - Similarly, \(\{b_n\}\) converges to \(L_2\) means for every \(\epsilon > 0\), there exists a positive integer \(N_2\) such that for all \(n \geq N_2\), \(|b_n - L_2| < \epsilon\).

2. **Using \( N, \epsilon \) Methods:**
   - Combine the definitions of limits for each sequence in order to derive the relationship involving the products \(a_n \cdot b_n\).
   - Use properties of absolute values and algebraic manipulation to achieve the desired result.

3. **Proof Structure:**
   - Identify suitable \(N\) and \(\epsilon\) for proving the product convergence.
   - Formulate the proof to show \(\lim_{{n \to \infty}} (a_n \cdot b_n)\).

### Goal
Demonstrate that according to the defined properties
Transcribed Image Text:### Problem Statement Let \(\{a_n\}\) and \(\{b_n\}\) be convergent sequences such that \[ \lim_{{n \to \infty}} a_n = L_1 \] and \[ \lim_{{n \to \infty}} b_n = L_2. \] Prove, **using \(N, \epsilon \) type methods only**, that the limit operator is linear and distributes across products, such that \[ \lim_{{n \to \infty}} (a_n \cdot b_n) = L_1 \cdot L_2. \] ### Key Points - **Convergent Sequences:** Sequences \(\{a_n\}\) and \(\{b_n\}\) converge to \(L_1\) and \(L_2\) respectively. - **Limit Operator Linearity:** The objective is to show that the limit operator distributes across the product of two convergent sequences using \(N, \epsilon \) methods. ### Methodology 1. **Definitions:** - A sequence \(\{a_n\}\) converges to \(L_1\) means for every \(\epsilon > 0\), there exists a positive integer \(N_1\) such that for all \(n \geq N_1\), \(|a_n - L_1| < \epsilon\). - Similarly, \(\{b_n\}\) converges to \(L_2\) means for every \(\epsilon > 0\), there exists a positive integer \(N_2\) such that for all \(n \geq N_2\), \(|b_n - L_2| < \epsilon\). 2. **Using \( N, \epsilon \) Methods:** - Combine the definitions of limits for each sequence in order to derive the relationship involving the products \(a_n \cdot b_n\). - Use properties of absolute values and algebraic manipulation to achieve the desired result. 3. **Proof Structure:** - Identify suitable \(N\) and \(\epsilon\) for proving the product convergence. - Formulate the proof to show \(\lim_{{n \to \infty}} (a_n \cdot b_n)\). ### Goal Demonstrate that according to the defined properties
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