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Let ABCD be a rectangle. Let Q be a point on the segment DC and P be the intersection of segment AQ and segment BD. If DQ = =DC, then prove that DP 1 n+1 = DB.

Let ABCD be a rectangle. Let Q be a point on the segment DC and P be the intersection of segment AQ and segment BD. If DQ = =DC, then prove that DP 1 n+1 = DB.

Elementary Geometry For College Students, 7e
Elementary Geometry For College Students, 7e
7th Edition
ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.
ChapterP: Preliminary Concepts
SectionP.CT: Test
Problem 1CT
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Let \( ABCD \) be a rectangle. Let \( Q \) be a point on the segment \( DC \) and \( P \) be the intersection of segment \( AQ \) and segment \( BD \). If \( DQ = \frac{1}{n} DC \), then prove that \( DP = \frac{1}{n+1} DB \).
Transcribed Image Text:Let \( ABCD \) be a rectangle. Let \( Q \) be a point on the segment \( DC \) and \( P \) be the intersection of segment \( AQ \) and segment \( BD \). If \( DQ = \frac{1}{n} DC \), then prove that \( DP = \frac{1}{n+1} DB \).
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