Let A = p and q, B = not(p or q). Then the statement S = (not A) and B is

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 Let A = p and q, B = not(p or q). Then the statement S = (not A) and B is

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Step 1

GIVEN

A = p and q,

B = not(p or q).

Then the statement S = (not A) and B is ??

First, we translate the problem into symbolic logic notation. Indeed:

By our hypothesis we have that:

A:p \wedge q

B: \ \sim (p \vee q)

S: (\sim A)\wedge B

That is

S: (\sim (p\wedge q))\wedge(\sim (p \vee q))

 

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