Let A = <-4 4 0 and b= b₂ Show that the equation Ax=b does not have a solution for all possible b, 2 0 2 b3 describe the set of all b for which Ax=b does have a solution. How can it be shown that the equation Ax=b does not have a solution for all possible b? Choose the correct answe below. OA. Row reduce the matrix A to demonstrate that A has a pivot position in every row. B. Row reduce the matrix A to demonstrate that A does not have a pivot position in every row. C. Find a vector x for which Ax=b is the zero vector. OD. Row reduce the augmented matrix [A b ] to demonstrate that [Ab] has a pivot position in every row. OE. Find a vector b for which the solution to Ax=b is the zero vector. Describe the set of all b for which Ax=b does have a solution. 0=0 (Type an expression using b₁, b2, and b3 as the variables and 1 as the coefficient of b3.)

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Question
b₁
and b = b2
b3
describe the set of all b for which Ax= b does have a solution.
Let A =
1-2- -1
4 0
2 0 2
-4
Show that the equation Ax=b does not have a solution for all possible b, and
How can it be shown that the equation Ax=b does not have a solution for all possible b? Choose the correct answer
below.
OA. Row reduce the matrix A to demonstrate that A has a pivot position in every row.
B. Row reduce the matrix A to demonstrate that A does not have a pivot position in every row.
OC. Find a vector x for which Ax=b is the zero vector.
D. Row reduce the augmented matrix [ A b ] to demonstrate that [A b] has a pivot position in every row.
OE. Find a vector b for which the solution to Ax=b is the zero vector.
Describe the set of all b for which Ax=b does have a solution.
0=0
(Type an expression using b₁, b₂, and b3 as the variables and 1 as the coefficient of b3.)
Transcribed Image Text:b₁ and b = b2 b3 describe the set of all b for which Ax= b does have a solution. Let A = 1-2- -1 4 0 2 0 2 -4 Show that the equation Ax=b does not have a solution for all possible b, and How can it be shown that the equation Ax=b does not have a solution for all possible b? Choose the correct answer below. OA. Row reduce the matrix A to demonstrate that A has a pivot position in every row. B. Row reduce the matrix A to demonstrate that A does not have a pivot position in every row. OC. Find a vector x for which Ax=b is the zero vector. D. Row reduce the augmented matrix [ A b ] to demonstrate that [A b] has a pivot position in every row. OE. Find a vector b for which the solution to Ax=b is the zero vector. Describe the set of all b for which Ax=b does have a solution. 0=0 (Type an expression using b₁, b₂, and b3 as the variables and 1 as the coefficient of b3.)
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