Let A be an mxn matrix, and let B and C have sizes for which the indicated sums and products are defined. Prove that A(B and that (B+C)A = BA + CA. Use the row-column rule. The (ij)-entry in A(B+C) can be written in either of the two ways bel a₁1 (b₁j + C1j) +...+ain (Dnj + Cnj) or n Σaik (bki + Cki) k=1 Prove that A(B+C) = AB + AC. Choose the correct answer below. n O A. a The (ij)-entry of A(B+C) equals the (ij)-entry of AB + AC, because Σaik (bki + Cki) = Σaikki - Σ ªik kj k=1 k=1 k=1 B. The (ij)-entry of A(B+C) equals the (ij)-entry of AB + AC, because aik (bj + Ckj) = Σ ªikºkj k=1 k=1 + n Σaikki k=1 O C. The (ij)-entry of A(B+C) equals the (ij)-entry of AB + AC, because Σaik (bki + Cki) = Σ akibjk - + • Σ ou (tu * 54 ) = Σ Buty - Ė Puser Sakisk k=1 k=1 k=1

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
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Let A be an mxn matrix, and let B and C have sizes for which the indicated sums and products are defined. Prove that A(B+C) = AB + AC
and that (B+C)A= BA + CA. Use the row-column rule. The (ij)-entry in A(B+C) can be written in either of the two ways below.
a¡1
a₁1 (₁j+C₁j) +...+ain (Dnj + Cnj)
or
Σaik (bki + Cki)
k=1
Prove that A(B+C) = AB + AC. Choose the correct answer below.
n
a
O A.
The (ij)-entry of A(B+C) equals the (ij)-entry of AB + AC, because Σaik (bki + Cki) = Σ aikoki - Σ ªik kj"
k=1
k=1
k=1
O B.
The (i.j)-entry of A(B+C) equals the (ij)-entry of AB + AC, because Σak (Dki +Ckj) = Σ ªikÞki + Σ
= EAN-ENGE
灯
k=1
k=1
k=1
aikki
O C.
n
n
The (i.j)-entry of A(B+C) equals the (ij)-entry of AB + AC, because Σ aik (bki +Ckj) = Σ akibjk + Σ akijk
k=1
k=1
k=1
Transcribed Image Text:Let A be an mxn matrix, and let B and C have sizes for which the indicated sums and products are defined. Prove that A(B+C) = AB + AC and that (B+C)A= BA + CA. Use the row-column rule. The (ij)-entry in A(B+C) can be written in either of the two ways below. a¡1 a₁1 (₁j+C₁j) +...+ain (Dnj + Cnj) or Σaik (bki + Cki) k=1 Prove that A(B+C) = AB + AC. Choose the correct answer below. n a O A. The (ij)-entry of A(B+C) equals the (ij)-entry of AB + AC, because Σaik (bki + Cki) = Σ aikoki - Σ ªik kj" k=1 k=1 k=1 O B. The (i.j)-entry of A(B+C) equals the (ij)-entry of AB + AC, because Σak (Dki +Ckj) = Σ ªikÞki + Σ = EAN-ENGE 灯 k=1 k=1 k=1 aikki O C. n n The (i.j)-entry of A(B+C) equals the (ij)-entry of AB + AC, because Σ aik (bki +Ckj) = Σ akibjk + Σ akijk k=1 k=1 k=1
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