Let (A,) be a group. Let B be a subset of A such that 2|B| > |A|. Show that, for any a in A, a = b₁ b₂ for some by and b₂ in B. (One approach could be to consider set C = {a ★ b¹ | b € B})
Let (A,) be a group. Let B be a subset of A such that 2|B| > |A|. Show that, for any a in A, a = b₁ b₂ for some by and b₂ in B. (One approach could be to consider set C = {a ★ b¹ | b € B})
Elements Of Modern Algebra
8th Edition
ISBN:9781285463230
Author:Gilbert, Linda, Jimmie
Publisher:Gilbert, Linda, Jimmie
Chapter3: Groups
Section3.4: Cyclic Groups
Problem 30E
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![5. Let (A,*) be a group. Let B be a subset of A such that 2|B| > |A|. Show that, for any a in A,
a = b₁ b₂ for some b, and b₂ in B. (One approach could be to consider set C = {ab¹ | b € B})](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F5afe79ca-9562-47a4-ba22-fc46ad709313%2Fd1eb5a4e-897c-4f63-b8f9-e13e9ba1dd17%2Ftrysh8_processed.jpeg&w=3840&q=75)
Transcribed Image Text:5. Let (A,*) be a group. Let B be a subset of A such that 2|B| > |A|. Show that, for any a in A,
a = b₁ b₂ for some b, and b₂ in B. (One approach could be to consider set C = {ab¹ | b € B})
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