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Let (a, b, c) and (u, v, w) be two vectors, and suppose that a, b, c, u, v, w > 1. What can we conclude? I|(a, b, c) × (u, v, w) ||2 1 ||(a, b, c) – (u, v, w) ||2 1. (a, b, c) and (u, v, w) are not orthogonal. (a, b, c) · (u, v, w) > 1

Let (a, b, c) and (u, v, w) be two vectors, and suppose that a, b, c, u, v, w > 1. What can we conclude? I|(a, b, c) × (u, v, w) ||2 1 ||(a, b, c) – (u, v, w) ||2 1. (a, b, c) and (u, v, w) are not orthogonal. (a, b, c) · (u, v, w) > 1

Algebra and Trigonometry (6th Edition)
Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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Explain why these statements are true or false.

Let (a, b, c) and (u, v, w) be two vectors, and suppose that а, b, с, и, v, w 2 1. What can we conclude? I|(a, b, c) × (u, v, w) || 1 (а, b, c) — (и, v, w) ||2 1. (a, b, c) and (u, v, w) are not orthogonal. (a, b, c) · (u, v, w) > 1
Transcribed Image Text:Let (a, b, c) and (u, v, w) be two vectors, and suppose that а, b, с, и, v, w 2 1. What can we conclude? I|(a, b, c) × (u, v, w) || 1 (а, b, c) — (и, v, w) ||2 1. (a, b, c) and (u, v, w) are not orthogonal. (a, b, c) · (u, v, w) > 1
Question 1 Suppose ū, v E R³ have the property that ||ū ||= 2, || 7 ||= 3 and ū · i = 0. Which of the following is true? üxi = 0 ||ū xv |= 6 ||à xi ||= 0 ů xi = 6 Question 2 Suppose ủ, v E R³. Which of the following statements is necessarily true? (ũ + V) × (ủ – †) = 2ü × v (ũ + v) × (û – v) = ù ×v (ũ + v) × (ủ – †) = 2v x ủ (ủ + v) × (ủ – v) = (ū x ū) – (v × v) (ũ + v) × (û – v) = Ō
Transcribed Image Text:Question 1 Suppose ū, v E R³ have the property that ||ū ||= 2, || 7 ||= 3 and ū · i = 0. Which of the following is true? üxi = 0 ||ū xv |= 6 ||à xi ||= 0 ů xi = 6 Question 2 Suppose ủ, v E R³. Which of the following statements is necessarily true? (ũ + V) × (ủ – †) = 2ü × v (ũ + v) × (û – v) = ù ×v (ũ + v) × (ủ – †) = 2v x ủ (ủ + v) × (ủ – v) = (ū x ū) – (v × v) (ũ + v) × (û – v) = Ō
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