Let A, B, and C be sets. Is the following equality true or false? A x (BUC) = (A × B) U (A × C')

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**Mathematical Set Theory: Cartesian Products and Unions**

**Problem Statement:**

Let \( A, B, \) and \( C \) be sets. Is the following equality true or false?

\[
A \times (B \cup C) = (A \times B) \cup (A \times C)
\]

**Explanation:**

To evaluate this, we need to understand the operations involved:

1. **Union (\(\cup\))**:
   - The union of sets \( B \) and \( C \), denoted \( B \cup C \), is the set of elements that are in \( B \), in \( C \), or in both.

2. **Cartesian Product (\(\times\))**:
   - The Cartesian product of \( A \) and another set, say \( D \), denoted \( A \times D \), is the set of all ordered pairs \((a, d)\) where \( a \in A \) and \( d \in D \).

**Verification:**

The left side of the equality, \( A \times (B \cup C) \), represents the set of ordered pairs where the first element is from \( A \) and the second element is from \( B \cup C \). Thus, each pair takes the form \((a, x)\), where \( a \in A \) and \( x \in B \cup C \).

The right side, \((A \times B) \cup (A \times C)\), represents the union of two Cartesian products: \( A \times B \), which are pairs \((a, b)\) with \( a \in A \) and \( b \in B \), and \( A \times C \), which are pairs \((a, c)\) with \( a \in A \) and \( c \in C \).

**Conclusion:**

Both sides of the equation describe the same set of ordered pairs. Therefore, the equality is true.

The equality demonstrates that taking the Cartesian product of a set \( A \) with the union of two sets \( B \) and \( C \) is equivalent to taking the union of the Cartesian products of \( A \) with \( B \) and \( A \) with \( C \).
Transcribed Image Text:**Mathematical Set Theory: Cartesian Products and Unions** **Problem Statement:** Let \( A, B, \) and \( C \) be sets. Is the following equality true or false? \[ A \times (B \cup C) = (A \times B) \cup (A \times C) \] **Explanation:** To evaluate this, we need to understand the operations involved: 1. **Union (\(\cup\))**: - The union of sets \( B \) and \( C \), denoted \( B \cup C \), is the set of elements that are in \( B \), in \( C \), or in both. 2. **Cartesian Product (\(\times\))**: - The Cartesian product of \( A \) and another set, say \( D \), denoted \( A \times D \), is the set of all ordered pairs \((a, d)\) where \( a \in A \) and \( d \in D \). **Verification:** The left side of the equality, \( A \times (B \cup C) \), represents the set of ordered pairs where the first element is from \( A \) and the second element is from \( B \cup C \). Thus, each pair takes the form \((a, x)\), where \( a \in A \) and \( x \in B \cup C \). The right side, \((A \times B) \cup (A \times C)\), represents the union of two Cartesian products: \( A \times B \), which are pairs \((a, b)\) with \( a \in A \) and \( b \in B \), and \( A \times C \), which are pairs \((a, c)\) with \( a \in A \) and \( c \in C \). **Conclusion:** Both sides of the equation describe the same set of ordered pairs. Therefore, the equality is true. The equality demonstrates that taking the Cartesian product of a set \( A \) with the union of two sets \( B \) and \( C \) is equivalent to taking the union of the Cartesian products of \( A \) with \( B \) and \( A \) with \( C \).
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