Let A and B be square matrices. Show that if AB = I then A and B are both invertible, with B =A1 and A=B¯¹ It is given that AB = I. The Invertible Matrix Theorem states that if there is an nxn matrix B such that AB = I, then it is true that It is given that AB = I. The Invertible Matrix Theorem states that if there is an nxn matrix A such that AB = I, then it is true that It is given that AB = I. Left-multiply each side of the equation by A¯ 1 A¹AB = A¹I = A-1 Left-multiply by A1 Simplify. It is given that AB = I. Right-multiply each side of the equation by B¹ ABB 1 = IB = B1 In conclusion, it can be stated that A and B Right-multiply by B1 Simplify. with B = and A=

Linear Algebra: A Modern Introduction
4th Edition
ISBN:9781285463247
Author:David Poole
Publisher:David Poole
Chapter7: Distance And Approximation
Section7.1: Inner Product Spaces
Problem 16AEXP
Question
Let A and B be square matrices. Show that if AB = I then A and B are both invertible, with B =A1 and A=B¯¹
It is given that AB = I. The Invertible Matrix Theorem states that if there is an nxn matrix B such that AB = I, then it is true that
It is given that AB = I. The Invertible Matrix Theorem states that if there is an nxn matrix A such that AB = I, then it is true that
It is given that AB = I. Left-multiply each side of the equation by A¯ 1
A¹AB = A¹I
= A-1
Left-multiply by A1
Simplify.
It is given that AB = I. Right-multiply each side of the equation by B¹
ABB 1 = IB
= B1
In conclusion, it can be stated that A and B
Right-multiply by B1
Simplify.
with B =
and A=
Transcribed Image Text:Let A and B be square matrices. Show that if AB = I then A and B are both invertible, with B =A1 and A=B¯¹ It is given that AB = I. The Invertible Matrix Theorem states that if there is an nxn matrix B such that AB = I, then it is true that It is given that AB = I. The Invertible Matrix Theorem states that if there is an nxn matrix A such that AB = I, then it is true that It is given that AB = I. Left-multiply each side of the equation by A¯ 1 A¹AB = A¹I = A-1 Left-multiply by A1 Simplify. It is given that AB = I. Right-multiply each side of the equation by B¹ ABB 1 = IB = B1 In conclusion, it can be stated that A and B Right-multiply by B1 Simplify. with B = and A=
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