Let A and B be events in a sample space S such that P(A) = .4 and P(BA) = 2. Find: P(ANB). OP(AB)-0.99 O PAB)-0.97 O PAB)-0.08 OPAB)-0.25 Finder 2 NOV 11
Let A and B be events in a sample space S such that P(A) = .4 and P(BA) = 2. Find: P(ANB). OP(AB)-0.99 O PAB)-0.97 O PAB)-0.08 OPAB)-0.25 Finder 2 NOV 11
A First Course in Probability (10th Edition)
10th Edition
ISBN:9780134753119
Author:Sheldon Ross
Publisher:Sheldon Ross
Chapter1: Combinatorial Analysis
Section: Chapter Questions
Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...
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![**Question 2** (1 point)
Let \( A \) and \( B \) be events in a sample space \( S \) such that \( P(A) = 0.4 \) and \( P(B \mid A) = 0.2 \). Find \( P(A \cap B) \).
Choices:
- \( P(A \cap B) = 0.99 \)
- \( P(A \cap B) = 0.97 \)
- \( P(A \cap B) = 0.08 \)
- \( P(A \cap B) = 0.25 \)
**Explanation:**
To solve for \( P(A \cap B) \), you can use the formula for conditional probability:
\[ P(B \mid A) = \frac{P(A \cap B)}{P(A)} \]
Given:
\( P(A) = 0.4 \)
\( P(B \mid A) = 0.2 \)
Substitute the values into the formula:
\[ 0.2 = \frac{P(A \cap B)}{0.4} \]
Solving for \( P(A \cap B) \):
\[ P(A \cap B) = 0.2 \times 0.4 = 0.08 \]
Correct choice: \( P(A \cap B) = 0.08 \)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F7617e6a3-d280-4f44-97ed-ed73937ef3e9%2Fc0900974-440a-44fb-a317-603824742b70%2F5c0318_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Question 2** (1 point)
Let \( A \) and \( B \) be events in a sample space \( S \) such that \( P(A) = 0.4 \) and \( P(B \mid A) = 0.2 \). Find \( P(A \cap B) \).
Choices:
- \( P(A \cap B) = 0.99 \)
- \( P(A \cap B) = 0.97 \)
- \( P(A \cap B) = 0.08 \)
- \( P(A \cap B) = 0.25 \)
**Explanation:**
To solve for \( P(A \cap B) \), you can use the formula for conditional probability:
\[ P(B \mid A) = \frac{P(A \cap B)}{P(A)} \]
Given:
\( P(A) = 0.4 \)
\( P(B \mid A) = 0.2 \)
Substitute the values into the formula:
\[ 0.2 = \frac{P(A \cap B)}{0.4} \]
Solving for \( P(A \cap B) \):
\[ P(A \cap B) = 0.2 \times 0.4 = 0.08 \]
Correct choice: \( P(A \cap B) = 0.08 \)
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