Let à (6, 7, 4) and 6=(3,2,2). = (a - b) × (a + b) i

Calculus: Early Transcendentals
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Chapter1: Functions And Models
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Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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### Vector Operations 

Given two vectors:
\[
\vec{a} = \begin{pmatrix} 6 \\ 7 \\ -4 \end{pmatrix} \quad \text{and} \quad \vec{b} = \begin{pmatrix} 3 \\ 2 \\ 2 \end{pmatrix}
\]

We need to find the value of the expression:
\[
(\vec{a} - \vec{b}) \times (\vec{a} + \vec{b})
\]

To solve this, follow these steps:

1. **Calculate \(\vec{a} - \vec{b}\):**

\[
\vec{a} - \vec{b} = \begin{pmatrix} 6 \\ 7 \\ -4 \end{pmatrix} - \begin{pmatrix} 3 \\ 2 \\ 2 \end{pmatrix} = \begin{pmatrix}  6 - 3 \\ 7 - 2 \\ -4 - 2 \end{pmatrix} = \begin{pmatrix} 3 \\ 5 \\ -6 \end{pmatrix}
\]

2. **Calculate \(\vec{a} + \vec{b}\):**

\[
\vec{a} + \vec{b} = \begin{pmatrix} 6 \\ 7 \\ -4 \end{pmatrix} + \begin{pmatrix} 3 \\ 2 \\ 2 \end{pmatrix} = \begin{pmatrix} 6 + 3 \\ 7 + 2 \\ -4 + 2 \end{pmatrix} = \begin{pmatrix} 9 \\ 9 \\ -2 \end{pmatrix}
\]

3. **Compute the cross product:**

Let \(\vec{u} = \vec{a} - \vec{b} = \begin{pmatrix} 3 \\ 5 \\ -6 \end{pmatrix}\) and \(\vec{v} = \vec{a} + \vec{b} = \begin{pmatrix} 9 \\ 9 \\ -2 \end{pmatrix}\).

The cross product \(\vec{u} \times \vec{v}\) is computed as follows:

\[
\vec{u} \times \vec{v} =
Transcribed Image Text:### Vector Operations Given two vectors: \[ \vec{a} = \begin{pmatrix} 6 \\ 7 \\ -4 \end{pmatrix} \quad \text{and} \quad \vec{b} = \begin{pmatrix} 3 \\ 2 \\ 2 \end{pmatrix} \] We need to find the value of the expression: \[ (\vec{a} - \vec{b}) \times (\vec{a} + \vec{b}) \] To solve this, follow these steps: 1. **Calculate \(\vec{a} - \vec{b}\):** \[ \vec{a} - \vec{b} = \begin{pmatrix} 6 \\ 7 \\ -4 \end{pmatrix} - \begin{pmatrix} 3 \\ 2 \\ 2 \end{pmatrix} = \begin{pmatrix} 6 - 3 \\ 7 - 2 \\ -4 - 2 \end{pmatrix} = \begin{pmatrix} 3 \\ 5 \\ -6 \end{pmatrix} \] 2. **Calculate \(\vec{a} + \vec{b}\):** \[ \vec{a} + \vec{b} = \begin{pmatrix} 6 \\ 7 \\ -4 \end{pmatrix} + \begin{pmatrix} 3 \\ 2 \\ 2 \end{pmatrix} = \begin{pmatrix} 6 + 3 \\ 7 + 2 \\ -4 + 2 \end{pmatrix} = \begin{pmatrix} 9 \\ 9 \\ -2 \end{pmatrix} \] 3. **Compute the cross product:** Let \(\vec{u} = \vec{a} - \vec{b} = \begin{pmatrix} 3 \\ 5 \\ -6 \end{pmatrix}\) and \(\vec{v} = \vec{a} + \vec{b} = \begin{pmatrix} 9 \\ 9 \\ -2 \end{pmatrix}\). The cross product \(\vec{u} \times \vec{v}\) is computed as follows: \[ \vec{u} \times \vec{v} =
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