Let a = 1491000! and b = 1491000! - 11. Assume that inflation has run rampant at the time of this problem (or assume that we are talking about watermelons instead of dollars). Suppose there are two groups of people, group A and group B, such that each member of group A has exactly a dollars and every member of group B has exactly b dollars. If the total number of dollars between all members of group A and group B is 585a - 351 11, find the total number of people in group A or enter O if there is not enough information to determine this.

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
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Let a = 1491000! and b =
1491000!
- 11. Assume that inflation has run rampant at the time of this problem (or assume that we are talking about watermelons instead of
dollars). Suppose there are two groups of people, group A and group B, such that each member of group A has exactly a dollars and every member of group B has exactly b
dollars.
If the total number of dollars between all members of group A and group B is 585a - 351 · 11, find the total number of people in group A or enter O if there is not enough
information to determine this.
Transcribed Image Text:Let a = 1491000! and b = 1491000! - 11. Assume that inflation has run rampant at the time of this problem (or assume that we are talking about watermelons instead of dollars). Suppose there are two groups of people, group A and group B, such that each member of group A has exactly a dollars and every member of group B has exactly b dollars. If the total number of dollars between all members of group A and group B is 585a - 351 · 11, find the total number of people in group A or enter O if there is not enough information to determine this.
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