Let a₁ = 1 5 -1 a₂ -6 - 25 3 and b = 3 -5 . For what value(s) of h is b in the plane spanned by a, and a₂? h The value(s) of h is(are). (Use a comma to separate answers as needed.)

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
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PLEASE SOLVE BOTH I WILL GIVE THUMBS UP!!!!

**Linear Algebra Problem: Finding the Value of h**

Consider the following vectors defined in \(\mathbb{R}^3\):

\[
\mathbf{a_1} = \begin{bmatrix} 1 \\ 5 \\ -1 \end{bmatrix},\ \mathbf{a_2} = \begin{bmatrix} -6 \\ -25 \\ 3 \end{bmatrix}, \ \text{and} \ \mathbf{b} = \begin{bmatrix} 3 \\ -5 \\ h \end{bmatrix}
\]

**Question:**
For what value(s) of \(h\) is \(\mathbf{b}\) in the plane spanned by \(\mathbf{a_1}\) and \(\mathbf{a_2}\)?

To determine this, we must check if \(\mathbf{b}\) lies in the span of \(\mathbf{a_1}\) and \(\mathbf{a_2}\). This can be expressed as whether \(\mathbf{b}\) can be written as a linear combination of \(\mathbf{a_1}\) and \(\mathbf{a_2}\):

\[
c_1 \mathbf{a_1} + c_2 \mathbf{a_2} = \mathbf{b}
\]

This expands to the following system of linear equations:

\[
c_1 \begin{bmatrix} 1 \\ 5 \\ -1 \end{bmatrix} + c_2 \begin{bmatrix} -6 \\ -25 \\ 3 \end{bmatrix} = \begin{bmatrix} 3 \\ -5 \\ h \end{bmatrix}
\]

**Solution:**
Solve for \(c_1\), \(c_2\), and \(h\). 

The value(s) of \(h\) is(are) \(\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\). (Use a comma to separate answers as needed.)

[Solution Steps for the Instructor to Include]:
- Set up the augmented matrix from the system of equations.
- Row-reduce the matrix to determine the consistency of the system with respect to \(h\).
- Solve for \(h\) where appropriate, ensuring the solution vector satisfies the original system.

This exercise aims to understand vector spaces, linear combinations, and the geometric
Transcribed Image Text:**Linear Algebra Problem: Finding the Value of h** Consider the following vectors defined in \(\mathbb{R}^3\): \[ \mathbf{a_1} = \begin{bmatrix} 1 \\ 5 \\ -1 \end{bmatrix},\ \mathbf{a_2} = \begin{bmatrix} -6 \\ -25 \\ 3 \end{bmatrix}, \ \text{and} \ \mathbf{b} = \begin{bmatrix} 3 \\ -5 \\ h \end{bmatrix} \] **Question:** For what value(s) of \(h\) is \(\mathbf{b}\) in the plane spanned by \(\mathbf{a_1}\) and \(\mathbf{a_2}\)? To determine this, we must check if \(\mathbf{b}\) lies in the span of \(\mathbf{a_1}\) and \(\mathbf{a_2}\). This can be expressed as whether \(\mathbf{b}\) can be written as a linear combination of \(\mathbf{a_1}\) and \(\mathbf{a_2}\): \[ c_1 \mathbf{a_1} + c_2 \mathbf{a_2} = \mathbf{b} \] This expands to the following system of linear equations: \[ c_1 \begin{bmatrix} 1 \\ 5 \\ -1 \end{bmatrix} + c_2 \begin{bmatrix} -6 \\ -25 \\ 3 \end{bmatrix} = \begin{bmatrix} 3 \\ -5 \\ h \end{bmatrix} \] **Solution:** Solve for \(c_1\), \(c_2\), and \(h\). The value(s) of \(h\) is(are) \(\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\). (Use a comma to separate answers as needed.) [Solution Steps for the Instructor to Include]: - Set up the augmented matrix from the system of equations. - Row-reduce the matrix to determine the consistency of the system with respect to \(h\). - Solve for \(h\) where appropriate, ensuring the solution vector satisfies the original system. This exercise aims to understand vector spaces, linear combinations, and the geometric
The image shows a mathematical problem centered around vector spaces and linear algebra. Below is the transcription of the content suitable for an educational website.

---

**Linear Algebra Problem: Vector Spaces and Span**

Given the matrix \( A \) and vector \( b \):

\[
A = \begin{pmatrix}
1 & 0 & -6 \\
0 & 3 & -5 \\
-5 & 9 & 4
\end{pmatrix}
\]
\[
b = \begin{pmatrix}
9 \\
-2 \\
-29
\end{pmatrix}
\]

Denote the columns of \( A \) by \( \mathbf{a_1}, \mathbf{a_2}, \mathbf{a_3} \), and let \( W = \text{Span} \{ \mathbf{a_1}, \mathbf{a_2}, \mathbf{a_3} \} \).

**Questions:**

a. Is \( \mathbf{b} \) in \( \{ \mathbf{a_1}, \mathbf{a_2}, \mathbf{a_3} \} \)? How many vectors are in \( \{ \mathbf{a_1}, \mathbf{a_2}, \mathbf{a_3} \} \)?

b. Is \( \mathbf{b} \) in \( W \)? How many vectors are in \( W \)?

c. Show that \( \mathbf{a_2} \) is in \( W \). [Hint: Row operations are unnecessary.]

---

**Step-by-Step Solution:**

a. **Is \( \mathbf{b} \) in \( \{ \mathbf{a_1}, \mathbf{a_2}, \mathbf{a_3} \} \)? Select the correct choice below and, if necessary, fill in the answer box(es) to complete your choice.**

- A. \(\bigcirc\) No, \( \mathbf{b} \) is not in \( \{ \mathbf{a_1}, \mathbf{a_2}, \mathbf{a_3} \} \) since \( \mathbf{b} \) is not equal to \( \mathbf{a_1}, \mathbf{a_2}, \) or \( \mathbf{a_3} \).
  
- B. \(\bigcirc\) Yes,
Transcribed Image Text:The image shows a mathematical problem centered around vector spaces and linear algebra. Below is the transcription of the content suitable for an educational website. --- **Linear Algebra Problem: Vector Spaces and Span** Given the matrix \( A \) and vector \( b \): \[ A = \begin{pmatrix} 1 & 0 & -6 \\ 0 & 3 & -5 \\ -5 & 9 & 4 \end{pmatrix} \] \[ b = \begin{pmatrix} 9 \\ -2 \\ -29 \end{pmatrix} \] Denote the columns of \( A \) by \( \mathbf{a_1}, \mathbf{a_2}, \mathbf{a_3} \), and let \( W = \text{Span} \{ \mathbf{a_1}, \mathbf{a_2}, \mathbf{a_3} \} \). **Questions:** a. Is \( \mathbf{b} \) in \( \{ \mathbf{a_1}, \mathbf{a_2}, \mathbf{a_3} \} \)? How many vectors are in \( \{ \mathbf{a_1}, \mathbf{a_2}, \mathbf{a_3} \} \)? b. Is \( \mathbf{b} \) in \( W \)? How many vectors are in \( W \)? c. Show that \( \mathbf{a_2} \) is in \( W \). [Hint: Row operations are unnecessary.] --- **Step-by-Step Solution:** a. **Is \( \mathbf{b} \) in \( \{ \mathbf{a_1}, \mathbf{a_2}, \mathbf{a_3} \} \)? Select the correct choice below and, if necessary, fill in the answer box(es) to complete your choice.** - A. \(\bigcirc\) No, \( \mathbf{b} \) is not in \( \{ \mathbf{a_1}, \mathbf{a_2}, \mathbf{a_3} \} \) since \( \mathbf{b} \) is not equal to \( \mathbf{a_1}, \mathbf{a_2}, \) or \( \mathbf{a_3} \). - B. \(\bigcirc\) Yes,
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