Let 8 = {(1, 1, 0), (0, 1, 1), (1, 0, 1)} and 8' = {(1, 0, 0), (0, 1, 0), (0, 0, 1)) be bases for R², and let 3 -1 A = 2 be the matrix for 7: R³ R³ relative to 8. (a) Find the transition matrix P from 8' to 8. 1/2 1/2 -1/2 -1/2 1/2 1/2 P= 1/2 -1/2 1/2 11 (b) Use the matrices and A to find [v] and [7(v)], where [v]=[-1 10]. 0 1 [v] = -1 1/2 [7(v)]= -1/2 1/2 (c) Find and A' (the matrix for 7 relative to 8). 1 0 1 p=d= 1 0 0 1/2 -1/2 1/2 A'= N/~ N/a N/W 1 -1 2 1 ↓1 x (d) Find [7(v)] two ways. [7(v)]g. =P~¹[7(v)], 1 -3/2 5/2 1/2 ·1 -1 11 T

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
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Let 8 = {(1, 1, 0), (0, 1, 1), (1, 0, 1)} and 8' = {(1, 0, 0), (0, 1, 0), (0, 0, 1)) be bases for R², and let
3
-1
A =
2
be the matrix for 7: R³ R³ relative to 8.
(a) Find the transition matrix P from 8' to 8.
1/2
1/2
-1/2
-1/2
1/2
1/2
P=
1/2
-1/2
1/2
11
(b) Use the matrices and A to find [v] and [7(v)], where
[v]=[-1 10].
0
1
[v] =
-1
1/2
[7(v)]=
-1/2
1/2
(c) Find and A' (the matrix for 7 relative to 8).
1
0
1
p=d=
1
0
0
1/2
-1/2
1/2
A'=
N/~ N/a N/W
1
-1
2
1
↓1
x
(d) Find [7(v)] two ways.
0
[7(v)]g. =P~¹[7(v)]g
-1
1
-3/2
5/2
1/2
↓t
11
11
Transcribed Image Text:Let 8 = {(1, 1, 0), (0, 1, 1), (1, 0, 1)} and 8' = {(1, 0, 0), (0, 1, 0), (0, 0, 1)) be bases for R², and let 3 -1 A = 2 be the matrix for 7: R³ R³ relative to 8. (a) Find the transition matrix P from 8' to 8. 1/2 1/2 -1/2 -1/2 1/2 1/2 P= 1/2 -1/2 1/2 11 (b) Use the matrices and A to find [v] and [7(v)], where [v]=[-1 10]. 0 1 [v] = -1 1/2 [7(v)]= -1/2 1/2 (c) Find and A' (the matrix for 7 relative to 8). 1 0 1 p=d= 1 0 0 1/2 -1/2 1/2 A'= N/~ N/a N/W 1 -1 2 1 ↓1 x (d) Find [7(v)] two ways. 0 [7(v)]g. =P~¹[7(v)]g -1 1 -3/2 5/2 1/2 ↓t 11 11
A'=
1/2
-1/2
1/2
-1
2
1
11
X
(d) Find [7(v)] two ways.
0
1
[7(v)]g. =P~¹[7(v)],
-1
=
[7(v)]g. = A'[v]g. =
X
0
1
-1
-3/2
5/2
1/2
1
11
Transcribed Image Text:A'= 1/2 -1/2 1/2 -1 2 1 11 X (d) Find [7(v)] two ways. 0 1 [7(v)]g. =P~¹[7(v)], -1 = [7(v)]g. = A'[v]g. = X 0 1 -1 -3/2 5/2 1/2 1 11
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