Let 7(t) = < - 2t³ – 3, tª + 2tª, – 4ln(2t) > Find a parametric equation of the line tangent to 7 (t) at the point ( – 5, 3, – 2.773) x(t) = - 5 – 6t y(t) = z(t) = %3D
Let 7(t) = < - 2t³ – 3, tª + 2tª, – 4ln(2t) > Find a parametric equation of the line tangent to 7 (t) at the point ( – 5, 3, – 2.773) x(t) = - 5 – 6t y(t) = z(t) = %3D
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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![Let 7(t) = < - 2t3 – 3, t4 + 2t4, – 4ln(2t) >
Find a parametric equation of the line tangent to 7(t) at the point (- 5, 3, – 2.773)
x(t) = – 5 – 6t
y(t) =
z(t)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F08a1092a-53fa-45f1-8cc5-326ab3991212%2F44b80233-5d20-4ec2-b559-414a4e04ecb3%2F572ztv_processed.png&w=3840&q=75)
Transcribed Image Text:Let 7(t) = < - 2t3 – 3, t4 + 2t4, – 4ln(2t) >
Find a parametric equation of the line tangent to 7(t) at the point (- 5, 3, – 2.773)
x(t) = – 5 – 6t
y(t) =
z(t)
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