Let 5n + 14n 3n - 5n2 - 23 bn 3n? Calculate the limit. (Give an exact answer. Use symbolic notation and fractions where needed. Enter DNE if the limit does not exist.) an lim Determine the convergence or divergence of an. n=1 E an diverges by the Limit Comparison Test because lim an is finite and b, diverges. n=1 n=1 а, a, converges by the Limit Comparison Test because lim is finite and b, converges. n=1 n=1 00 Σ an converges by the Limit Comparison Test because lim an is finite and bn diverges. n=1 n=l It is not possible to use the Limit Comparison Test to determine the convergence or divergence of an- n=1 II

Elementary Geometry For College Students, 7e
7th Edition
ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.
Chapter8: Areas Of Polygons And Circles
Section8.4: Cicumference And Area Of A Cicle
Problem 21E: Let N be any point on side BC of the right triangle ABC. Find the upper and lower limits for the...
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Let
5n? + 14n
5
3n – 5n2 – 23
bn
3n?
Calculate the limit.
(Give an exact answer. Use symbolic notation and fractions where needed. Enter DNE if the limit does not exist.)
an
lim
Determine the convergence or divergence of an.
an
E an diverges by the Limit Comparison Test because lim
is finite and E b, diverges.
n=1
n=1
a, converges by the Limit Comparison Test because lim
is finite and b, converges.
n=1
n=1
00
Σ
an converges by the Limit Comparison Test because lim
an
is finite and bn diverges.
no b,
n=1
n=l
It is not possible to use the Limit Comparison Test to determine the convergence or divergence of Ea
an-
n=1
II
Transcribed Image Text:Let 5n? + 14n 5 3n – 5n2 – 23 bn 3n? Calculate the limit. (Give an exact answer. Use symbolic notation and fractions where needed. Enter DNE if the limit does not exist.) an lim Determine the convergence or divergence of an. an E an diverges by the Limit Comparison Test because lim is finite and E b, diverges. n=1 n=1 a, converges by the Limit Comparison Test because lim is finite and b, converges. n=1 n=1 00 Σ an converges by the Limit Comparison Test because lim an is finite and bn diverges. no b, n=1 n=l It is not possible to use the Limit Comparison Test to determine the convergence or divergence of Ea an- n=1 II
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