Let -4x³ - 2y³ - 3x3 + 2xyz — 322 = 0. дz Oz Use partial derivatives to calculate and at the point (-3,-5, -2). Әх ду Oz дx (-3,-5,-2) Oz ду (-3,-5,-2) -
Let -4x³ - 2y³ - 3x3 + 2xyz — 322 = 0. дz Oz Use partial derivatives to calculate and at the point (-3,-5, -2). Әх ду Oz дx (-3,-5,-2) Oz ду (-3,-5,-2) -
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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![**Question 14**
Let \(-4x^3 - 2y^3 - 3z^3 + 2xyz = 322\).
Use partial derivatives to calculate \(\frac{\partial z}{\partial x}\) and \(\frac{\partial z}{\partial y}\) at the point \((-3, -5, -2)\).
\[
\left[ \frac{\partial z}{\partial x} \right]_{(-3,-5,-2)} = \_\_\_\_\_\_
\]
\[
\left[ \frac{\partial z}{\partial y} \right]_{(-3,-5,-2)} = \_\_\_\_\_\_
\]
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Transcribed Image Text:**Question 14**
Let \(-4x^3 - 2y^3 - 3z^3 + 2xyz = 322\).
Use partial derivatives to calculate \(\frac{\partial z}{\partial x}\) and \(\frac{\partial z}{\partial y}\) at the point \((-3, -5, -2)\).
\[
\left[ \frac{\partial z}{\partial x} \right]_{(-3,-5,-2)} = \_\_\_\_\_\_
\]
\[
\left[ \frac{\partial z}{\partial y} \right]_{(-3,-5,-2)} = \_\_\_\_\_\_
\]
Question Help: [Video]
[Submit Question]
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