Let 2x-4/x-1 (d) Determine intervals on which the function is increasing; determine intervals on which the function is decreasing. (h) With the aid of the information obtained in parts (a) - (g), give a reasonable sketch of the curve.   (a) X=2   (2,0) Y=4   (0,4)   (g) To find the inflection point, we need to find the value for which the double derivative is equal to 0. f''(x)−4(x−1)3−4===000f''(x)=0-4(x-1)3=0-4=0 This statement is false because −4≠0-4≠0 for any real value of x. Since f''(x) cannot be equal to zero for any real value of x, therefore there is no inflection point.   Answer: (e) No relative maxima and no relative minima. (f) Function f(x) is concave up over the interval (−∞,1)(-∞,1) and concave down over the interval (1,∞)(1,∞). (g) There is no inflection point.

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
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Let 2x-4/x-1

(d) Determine intervals on which the function is increasing; determine intervals on which the function is decreasing.

(h) With the aid of the information obtained in parts (a) - (g), give a reasonable sketch of the curve.

 

(a)

X=2   (2,0)

Y=4   (0,4)

 

(g)

To find the inflection point, we need to find the value for which the double derivative is equal to 0.

f''(x)−4(x−1)3−4===000f''(x)=0-4(x-1)3=0-4=0

This statement is false because −4≠0-4≠0 for any real value of x.

Since f''(x) cannot be equal to zero for any real value of x, therefore there is no inflection point.

 

Answer: (e) No relative maxima and no relative minima.

(f) Function f(x) is concave up over the interval (−∞,1)(-∞,1) and concave down over the interval (1,∞)(1,∞).

(g) There is no inflection point.

 

please quickly

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