Let 11 1 2 14> : 11 Calculate 14> = |Q> (Normalize IQ>) Then find the probability that Q> is found in states 10>, 11>
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![Let
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14> =
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Calculate 14> = |Q> (Normalize IQ>)
Then find the probability that Q> is found in states 10>, |1>](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F0f7775f3-edad-4f27-ba1b-f7886a7505bd%2F12420291-276f-470a-83e6-593c100bf300%2Fp3ph8s4_processed.jpeg&w=3840&q=75)
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- he mean height of women in a country (ages 20minus−29) is 63.663.6 inches. A random sample of 5555 women in this age group is selected. What is the probability that the mean height for the sample is greater than 6464 inches? Assume sigmaσequals=2.892.89.Mean= 100 and standard deviation=10, what is probability of x<80 or x>110The time (in minutes) between arrivals of customers to a post office is to be modelled by the Exponential distribution with mean 0.62. Part a) What is the probability that the time between consecutive customers is less than 15 seconds? Part b) Find the probability that the time between consecutive customers is between ten and fifteen seconds. Part c) Given that the time between consecutive customers arriving is greater than ten seconds, what is the chance that it is greater than fifteen seconds?
- Central Limit Theorem: When the maximum SAT score was 2400, scores had a mean = 1518 and standard deviation = 325. Assuming the scores are normally distributed, determine the probability of a score exceeding 1600. If 81 SAT scores are randomly selected, find the probability that their mean score exceeds 1600.The mean incubation time of fertilized chicken eggs kept at 100.5 degrees F in a still-air incubator is 21 days. Suppose that the incubation times are approximately normally distributed with a standard deviation of 1 day. Find an interpret the probability that a a sample of 12 selected fertilized chicken egg hatches in less than 20 days. Edit View Insert Format Tools Table BI U 2. 12pt v Paragraph v B IThe time (in minutes) between arrivals of customers to a post office is to be modelled by the Exponential distribution with mean 0.6. Part a) What is the probability that the time between consecutive customers is less than 15 seconds? Part b) Find the probability that the time between consecutive customers is between ten and fifteen seconds. Part c) Given that the time between consecutive customers arriving is greater than ten seconds, what is the chance that it is greater than fifteen seconds?
- The time (in minutes) between arrivals of customers to a post office is to be modelled by the Exponential distribution with mean 0.680.68.Part a)What is the probability that the time between consecutive customers is less than 15 seconds?Part b)Find the probability that the time between consecutive customers is between ten and fifteen seconds.Part c)Given that the time between consecutive customers arriving is greater than ten seconds, what is the chance that it is greater than fifteen seconds?Use normal approximation to estimate the probability of getting less than 54 girls in 100 births. Assume that boys and girls are equally likely.What is the probability of randomly selecting an adult with a resting heart rate greater than 65 BPM? What is the probability of randomly selecting an adult who has resting heart rate less than 58 BPM?
- Use normal approximation to estimate the probability of getting less than 46 girls in 100 births. Assume that boys and girls are equally likely.Use normal approximation to estimate the probability of getting at most 47 girls in 100 births. Assume that boys and girls are equally likely.The time between arrivals of customers at the drive-up window of a bank follows an exponential distribution with a mean of 20 minutes. a)What is the probability that the arrival time between customers will be 13 minutes or less? b)What is the probability that the arrival time between customers will be between 13 and 27 minutes?
