9. **(Lesson 6.4)** Evaluate each integral without explicitly writing out the necessary substitution. In Part (b), you will need to rewrite the integral by dividing each term by 9.(a) \(\int_{0}^{0.2} \frac{4}{\sqrt{1-(2x)^2}} \, dx = \left. \underline{\hspace{3cm}} \right|_{0}^{0.2} = \underline{\hspace{4cm}}\)(b) \(\int_{1}^{4} \frac{18}{9+x^2} \, dx = \left. \underline{\hspace{3cm}} \right|_{1}^{4} = \underline{\hspace{4cm}}\)**Explanation:**- **Part (a)** involves evaluating an integral with limits from 0 to 0.2. The integrand is \(\frac{4}{\sqrt{1-(2x)^2}}\), which suggests a trigonometric substitution may simplify the expression.- **Part (b)** involves evaluating an integral with limits from 1 to 4. The integrand is \(\frac{18}{9+x^2}\). Before evaluating, it instructs to rewrite the integral by dividing each term by 9, suggesting simplification through partial fraction decomposition or a similar method.

Name: 9. **(Lesson 6.4)** Evaluate each integral without explicitly writing
Uploaded: 2024-03-20T06:46:14.000Z
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Description: 9. **(Lesson 6.4)** Evaluate each integral without explicitly writing out the necessary substitution. In Part (b), you will need to rewrite the integral by dividing each term by 9.(a) \(\int_{0}^{0.2} \frac{4}{\sqrt{1-(2x)^2}} \, dx = \left. \underl