LESSON 4: OPENER 600 The Smithville City Council has decided to build a new recreation center. The city has already purchased a 450-foot by 600-foot lot on which to construct the recreation center. A plan of the lot is shown here. 450 1. What is the perimeter of the lot? 2. What is the area of the lot? P the distance around A= total squares in the figure Ar = Area of a rectangle Ar = length times width -twice the length + twice the width - 21 + 2w or = twice the base + twice the hight 2b + 2w Recreation Center Ar = lw or Ar base times hight Ar = bh
LESSON 4: OPENER 600 The Smithville City Council has decided to build a new recreation center. The city has already purchased a 450-foot by 600-foot lot on which to construct the recreation center. A plan of the lot is shown here. 450 1. What is the perimeter of the lot? 2. What is the area of the lot? P the distance around A= total squares in the figure Ar = Area of a rectangle Ar = length times width -twice the length + twice the width - 21 + 2w or = twice the base + twice the hight 2b + 2w Recreation Center Ar = lw or Ar base times hight Ar = bh
Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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Lesson 4: More about expressions
LESSON 4: OPENER
The Smithville City Council has decided to build a new recreation center. The city
has already purchased a 450-foot by 600-foot lot on which to construct the
recreation center. A plan of the lot is shown here.
1. What is the perimeter of the lot?
2. What is the area of the lot?
A = total squares in the figure
Ar = Area of a rectangle
Ar = length times width
P= the distance around
= twice the length + twice the width
= 21 + 2w
or
Recreation Center
or
= twice the base + twice the hight
= 2b + 2w
Ar = lw
Ar = base times hight
Ar = bh
Question Details
Topic 3 Lesson 4: "More
about expressions"
Norms/Objectives
Homework
Class to-de the epener (5"
Transcribed Image Text:3:13
A goformative.com
T
Lesson 4: More about expressions
LESSON 4: OPENER
The Smithville City Council has decided to build a new recreation center. The city
has already purchased a 450-foot by 600-foot lot on which to construct the
recreation center. A plan of the lot is shown here.
1. What is the perimeter of the lot?
2. What is the area of the lot?
A = total squares in the figure
Ar = Area of a rectangle
Ar = length times width
P= the distance around
= twice the length + twice the width
= 21 + 2w
or
Recreation Center
or
= twice the base + twice the hight
= 2b + 2w
Ar = lw
Ar = base times hight
Ar = bh
Question Details
Topic 3 Lesson 4: "More
about expressions"
Norms/Objectives
Homework
Class to-de the epener (5
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A goformative.com
т
LESSON 4: CORE ACTIVITY
The city wants to ensure that the rooms in the recreation center are large enough that they can be used for lots
of different purposes. The architect draws a floor plan to help the project manager make decisions about the
dimensions of two of the rooms.
2x + 10
x + 10
Conference Room
Gymnasium
Determine the dimensions of the conference room and the gymnasium for different values of x. Then, find the
perimeter and area.
1.
Length
side in feet
Value of x
Room
shortest Length of longest
side in feet
Perimeter
Area
10
Conference room
Gymnasium
50
Conference room
Gymnasium
Question Details
We will do this problem
together using agilemind
pg.3. [ These problems
involve writing algebraic
expressions to represent
the perimeter and area
of several floor plans.
The concepts we will be"
Transcribed Image Text:3:14
A goformative.com
т
LESSON 4: CORE ACTIVITY
The city wants to ensure that the rooms in the recreation center are large enough that they can be used for lots
of different purposes. The architect draws a floor plan to help the project manager make decisions about the
dimensions of two of the rooms.
2x + 10
x + 10
Conference Room
Gymnasium
Determine the dimensions of the conference room and the gymnasium for different values of x. Then, find the
perimeter and area.
1.
Length
side in feet
Value of x
Room
shortest Length of longest
side in feet
Perimeter
Area
10
Conference room
Gymnasium
50
Conference room
Gymnasium
Question Details
We will do this problem
together using agilemind
pg.3. [ These problems
involve writing algebraic
expressions to represent
the perimeter and area
of several floor plans.
The concepts we will be
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