< Question 4 of 10 Calculate the pH when 20.0 mL of 0.150 M KOH is mixed with 45.0 mL of 0.300 M HBrO (Ka = 2.5 × 10-⁹)

Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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**Calculating the pH of a Mixed Solution**

In this exercise, you are asked to calculate the pH when 200.0 mL of 0.150 M KOH is mixed with 45.0 mL of 0.300 M HBFO. The acid dissociation constant (Ka) for HBFO is given as 2.5 x 10^-9.

### Steps to Calculate the pH:

1. **Determine the moles of KOH and HBFO.**
   - KOH: \( \text{moles} = \text{volume (L)} \times \text{molarity (M)} = 0.200 \, \text{L} \times 0.150 \, \text{M} \)
   - HBFO: \( \text{moles} = \text{volume (L)} \times \text{molarity (M)} = 0.045 \, \text{L} \times 0.300 \, \text{M} \)

2. **Determine the limiting reagent and the excess reagent.**
   - Calculate which reagent is in excess after the neutralization reaction.

3. **Calculate the concentration of excess reagent.**

4. **Use the Henderson-Hasselbalch equation if applicable.**

5. **Calculate the pH from the concentration of hydroxide or hydronium ions.**

### Additional Details:

- **Calculator Interface:**
  - Includes numbers 0-9, positive/negative toggle, and basic operations.
  - Functions to multiply by 10 and clear entries.

This interactive problem helps you practice buffer and neutralization chemistry concepts, using algebraic and logarithmic calculations to deduce the resulting pH.
Transcribed Image Text:**Calculating the pH of a Mixed Solution** In this exercise, you are asked to calculate the pH when 200.0 mL of 0.150 M KOH is mixed with 45.0 mL of 0.300 M HBFO. The acid dissociation constant (Ka) for HBFO is given as 2.5 x 10^-9. ### Steps to Calculate the pH: 1. **Determine the moles of KOH and HBFO.** - KOH: \( \text{moles} = \text{volume (L)} \times \text{molarity (M)} = 0.200 \, \text{L} \times 0.150 \, \text{M} \) - HBFO: \( \text{moles} = \text{volume (L)} \times \text{molarity (M)} = 0.045 \, \text{L} \times 0.300 \, \text{M} \) 2. **Determine the limiting reagent and the excess reagent.** - Calculate which reagent is in excess after the neutralization reaction. 3. **Calculate the concentration of excess reagent.** 4. **Use the Henderson-Hasselbalch equation if applicable.** 5. **Calculate the pH from the concentration of hydroxide or hydronium ions.** ### Additional Details: - **Calculator Interface:** - Includes numbers 0-9, positive/negative toggle, and basic operations. - Functions to multiply by 10 and clear entries. This interactive problem helps you practice buffer and neutralization chemistry concepts, using algebraic and logarithmic calculations to deduce the resulting pH.
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